# Mental Ability Tests on 'Alphabet and Number Sequences and Series' Set 121

## These questions help you develop speed and accuracy. Every exam tests these skills. So if you are preparing for a bank exam, state and national talent search exams, UGC NET, GATE, etc., then this quiz will help you master these skills. I have provided answers and solutions to each of the questions. This is quiz no. 121 in this series.

Last Reviewed and Updated on February 7, 2020
Posted by Parveen(Hoven),
Aptitude Trainer and Software Developer

## Quiz Questions

Each question has four choices. More than one option can be correct. After you have finished the quiz scroll towards the last question to view your result. I have provided solutions and answers to all the questions.

### Question 1

John is ranked 9th from the top and 7th from the bottom among the students who passed the annual examination. If the total number of failed students is 17, how many students appeared in the exam?

A

32

B

34

C

26

D

31

Soln.
Ans: A

Sum of positions of an item from top(right) and bottom(left) of a list is always equal to the sum of the positions of the first and last items. So total passed is = 9 + 7 - 1 = 15. Those appeared = failed + passed = 15 + 17 = 32.

Question ID: 16-02-10-11-59-51-601.
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### Question 2

In the number series given below, how many 7 are there that are not divisible by the number on their left but completely divisible by the number that is second to their right?

6 7 7 7 8 7 5 4 4 1 1 9 2 4 2 5 5 7 8

A

4

B

1

C

0

D

3

Soln.
Ans: B

At these locations: 6-7-7-7 ;

Question ID: 16-02-10-11-59-51-602.
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### Question 3

This is a series of digits that has been written by randomly arranging 19 digits. How many consequetive pairs of numbers does it contain?

8 1 3 6 5 6 2 5 8 6 6 9 1 7 8 4 5 4 6

A

8

B

4

C

0

D

5

Soln.
Ans: D

At these locations: 6-5 ;5-6 ;7-8 ;4-5 ;5-4 ;

Question ID: 16-02-10-11-59-51-603.
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### Question 4

If the following series is reversed, then which item comes at position 12 counted from the left? The series is:

Y D % O W X \$ 5 S B Z I 4 + P A K Q 2 V

A

K

B

5

C

S

D

X

Soln.
Ans: C

The item at position 12 is total items + 1 - 12 which is 20 + 1 - 12 = 9. Counting from the left we get S.

Question ID: 16-02-10-11-59-51-604.
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### Question 5

If the first half of the following series is reversed, then which item is 9th to the right of the 10th item from the right side? The series is:

Z 2 H I C Q F O 9 @ 1 G S D V U T R M 3

A

F

B

3

C

D

D

1

Soln.
Ans: B

Midpoint is 10. We have to find 20 - 10 + 9 = 19 + 1th item from the left side. Since the location lies in the right half, reversing the series has no effect in this zone. So counting from the left side, the item is 3.

Question ID: 16-02-10-11-59-51-605.
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