# Mental Ability Tests on 'Alphabet and Number Sequences and Series' Set 246

## These questions help you develop speed and accuracy. Every exam tests these skills. So if you are preparing for a bank exam, state and national talent search exams, UGC NET, GATE, etc., then this quiz will help you master these skills. I have provided answers and solutions to each of the questions. This is quiz no. 246 in this series.

Last Reviewed and Updated on August 18, 2019
Posted by Parveen(Hoven),
Aptitude Trainer and Software Developer

## Quiz Questions

Each question has four choices. More than one option can be correct. After you have finished the quiz scroll towards the last question to view your result. I have provided solutions and answers to all the questions.

### Question 1

If the following series is reversed, then which item comes at position 20 counted from the left? The series is:

B G N 2 9 X + R 3 @ F I K Q W 8 5 Y 7 1

A

N

B

Q

C

B

D

1

Soln.
Ans: C

The item at position 20 is total items + 1 - 20 which is 20 + 1 - 20 = 1. Counting from the left we get B.

Question ID: 16-02-10-11-59-51-1226.
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### Question 2

Study the following series.

F M T 8 R Q J H X Z E S 7 U W O 9 P 5 +

Find what should come in place of the question mark(?)

RX , ? , XE , ES

A

FR

B

RJ

C

JZ

D

XT

Soln.
Ans: C

There is a gap of 1 between the first characters of each of the given pair. The second character of each pair is decreasingly moving one position to the right of the first character.

Question ID: 16-02-10-11-59-51-1227.
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### Question 3

Sheela is ranked 16th from the top and 13th from the bottom among the students who passed the annual examination. If the total number of failed students is 11, how many students appeared in the exam?

A

32

B

38

C

39

D

44

Soln.
Ans: C

Sum of positions of an item from top(right) and bottom(left) of a list is always equal to the sum of the positions of the first and last items. So total passed is = 16 + 13 - 1 = 28. Those appeared = failed + passed = 28 + 11 = 39.

Question ID: 16-02-10-11-59-51-1228.
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### Question 4

This is a series of digits and alphabets. How many pairs are such that the consecutive items are both alphabets?

U 7 Y 5 3 9 3 T V 1 X E 1 6 8 A P O I 2

A

7

B

5

C

4

D

1

Soln.
Ans: B

At these locations: T-V ;X-E ;A-P ;P-O ;O-I ;

Question ID: 16-02-10-11-59-51-1229.
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### Question 5

How many pairs of letters are there in the word PICKABACKING which have as many letters between them in the word as in the English alphabet?

A

0

B

2

C

1

D

7

Soln.
Ans: D
1. pIcKabacking
2. pIckabaCking
3. piCkAbacking
4. pickABacking
5. pickaBAcking
6. pickabaCkinG
7. pickabackInG
Question ID: 16-02-10-11-59-51-1230.
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