Distance and Time Quiz Set 003

Let the speed of bus X be x, and of Y be 3x/2. The difference in the times taken by them is $18/x - 18/({3x}/2)$ = 2, which becomes 18 × $1/{3x}$ = 2. Solving, we get x = 3 km/h.

Let the normal speed be x km/hr. We have been given $15/x$ - $15/{x + 2}$ = 2. This translates to the quadratic equation $2x^2 + 4x - 30 = 0$, which can be solved to obtain x = 3 as the answer. If you don't want to solve the equation, then you can put each option into this equation and check that way. But this trick will work only if all the options have some numerical value.

We know 1m/s = $18/5$ kmph. So 30m/s = $18/5 × 30$ = 108 kmph.

By the given problem, the time is same for both cases. If the total distance covered by him at 2km/h is x, then, $x/2 = {x + 42}/9$. Solving, we obtain x = 12 km.

Let us suppose that he travels x km with the camel, and the remaining (260 - x) km with the car. Total time is $x/5 + {260 - x}/15 = 20.$ Solving, we get x = 20 km.