Distance and Time Quiz Set 020 | Maths Aptitude Quiz Questions and Mock Test on Distance and Time Set 20 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

A boy walks along the three edges of an equilateral triangle at average speeds of 6 km/h, 2 km/h and 9 km/h. What is the average speed along the whole journey?

$3{6/7}$ kmph.

$5{2/3}$ kmph.

$2{2/9}$ kmph.

$5{1/3}$ kmph.

Soln.
Ans: a

Let the edge of the triangle be L. Total distance travelled = 3L. Time taken = $L/6 + L/2 + L/9$. So overall average speed = ${3L}/{L/6 + L/2 + L/9}$ which simplifies to ${27/7}$, which is same as: $3{6/7}$ km/h.

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Question 2

A cyclist travels at a speed of 5km/h. Had he travelled at 10km/h he would have covered a distance of 15 km more. What is the total distance travelled by him?

15 km.

16 km.

14 km.

17 km.

Soln.
Ans: a

By the given problem, the time is same for both cases. If the total distance covered by him at 5km/h is x, then, $x/5 = {x + 15}/10$. Solving, we obtain x = 15 km.

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Question 3

A city bus has an average speed of 17 km/h if it doesn't stop anywhere. But if it stops in-between the average speed drops to 14 km/h. How many minutes does it stop in 1 hour?

$10{10/17}$ mins.

$12{5/16}$ mins.

$8{11/19}$ mins.

$12{3/19}$ mins.

Soln.
Ans: a

Due to stoppages, it covers a less distance of 17 - 14 = 3 in one hour. The time taken for that distance would be the wastage due to stopping = $3/17$ × 60 = $10{10/17}$ mins.

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Question 4

Speeds of A and B are in the ratio 7 : 8. What is the ratio of the times that they will take to cover a distance of 100 km?

8 : 7.

7 : 8.

8 : 100.

100 : 7.

Soln.
Ans: a

Let the speeds be 7x and 8x. The times they take to cover 100 km are $100/{7x}$ and $100/{8x}$. The ratio would be 8 : 7.

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Question 5

A boy walks along the three edges of an equilateral triangle at average speeds of 5 km/h, 8 km/h and 3 km/h. What is the average speed along the whole journey?

$4{44/79}$ kmph.

$5{49/78}$ kmph.

$3{38/81}$ kmph.

$7{10/27}$ kmph.

Soln.
Ans: a

Let the edge of the triangle be L. Total distance travelled = 3L. Time taken = $L/5 + L/8 + L/3$. So overall average speed = ${3L}/{L/5 + L/8 + L/3}$ which simplifies to ${360/79}$, which is same as: $4{44/79}$ km/h.

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