HCF and LCM Quiz Set 009 | Maths Aptitude Quiz Questions and Mock Test on HCF and LCM Set 9 | mock tests for Bank PO, SSB/SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

Which is the smallest number, which, when divided by 21 and 80, leaves the remainder 4?

1684.

1686.

1683.

1687.

Soln.
Ans: a

The LCM of 21 and 80 = 1680, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 1680 + 4 = 1684 is the required number.

Solution | Discuss! | Chapters»

Question 2

Which is the smallest number, which, when divided by 9 and 65, leaves the remainder 7?

592.

594.

591.

595.

Soln.
Ans: a

The LCM of 9 and 65 = 585, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 585 + 7 = 592 is the required number.

Solution | Discuss! | Chapters»

Question 3

Which is the smallest number, which, when divided by 21 and 75, leaves the remainder 3?

528.

530.

527.

531.

Soln.
Ans: a

The LCM of 21 and 75 = 525, is the smallest number, which, when divided by either of them leaves the remainder 0. Now adding, 525 + 3 = 528 is the required number.

Solution | Discuss! | Chapters»

Question 4

Which is the least number which must be added to 21937 so that it becomes divisible by 21, 95 and 77?

10.

Soln.
Ans: a

The LCM of 21, 95 and 77 = 21945. The lcm when divided by either of these numbers leaves the remainder 0. The minimum number to be added is 21945 - 21937 = 8.

Solution | Discuss! | Chapters»

Question 5

The sum of LCM and HCF of two numbers is 232. If LCM is 57 times the HCF, then the product of the two numbers is?

912.

914.

913.

915.

Soln.
Ans: a

Let L be the LCM, and H the HCF. Then H + L = 232, and L = 57H. Solving these for H, we get H = $232/{57 + 1}$ = 4, and L = 228. The product of the two numbers is equal to the product of the lcm and hcf = 4 × 228 = 912.

Solution | Discuss! | Chapters»