HCF and LCM Quiz Set 013

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Question 1

The product of LCM and HCF of two numbers is 3720? If one of the numbers is 62, what is the other?

 A

60.

 B

62.

 C

61.

 D

63.

Soln.
Ans: a

Product of two numbers is equal to the product of their LCM and HCF. So the other number is $3720/62$ = 60.

Solution | Discuss! | Chapters»

Question 2

What is the HCF of ${6/19}$, ${13/14}$ and $2{2/5}$?

 A

${1/1330}$.

 B

${1/665}$.

 C

${3/1330}$.

 D

${2/665}$.

Soln.
Ans: a

The HCF of numerators 6, 13 and 12 is 1. The LCM of denominators 19, 14 and 5 is 1330. So the required HCF of the given fractions is 1/1330 = ${1/1330}$.

Solution | Discuss! | Chapters»

Question 3

Three cyclists are cycling in a circular track. They, respectively, take 5, 13 and 22 minutes to complete the circle once. After how many minutes will they all again meet at a single point?

 A

1430 minutes.

 B

2860 minutes.

 C

715 minutes.

 D

1431 minutes.

Soln.
Ans: a

The answer lies in finding the LCM of their times. The LCM of 5, 13 and 22 = 1430.

Solution | Discuss! | Chapters»

Question 4

What is the HCF of (19 × 7), (7 × 6) and (6 × 19)?

 A

1.

 B

2.

 C

0.

 D

3.

Soln.
Ans: a

The required HCF is product of the three numbers divided by their LCM. The LCM of 19, 7 and 6 is 798. So the required HCF = ${19 × 7 × 6}/798$ = 1. Please note that LCM(n1, n2, n3) × HCF(n1 × n2, n2 × n3, n3 × n1) = n1 × n2 × n3.

Solution | Discuss! | Chapters»

Question 5

Two numbers are in the ratio 4 : 1. If their HCF and LCM are 4 and 16, which of these is the smaller number?

 A

4.

 B

8.

 C

16.

 D

2.

Soln.
Ans: a

Since the numbers are in an integral ratio, the LCM is equal to the larger number, and HCF is equal to the smaller number. So the smaller is 4.

Solution | Discuss! | Chapters»
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Updated on 2020-02-07. Published on: 2016-05-02

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