Logarithms Quiz Set 007

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Question 1

Suppose for the sake of this question that $\text"log"_3(6)$ = 12. Then what is $\text"log"_6(729)$?

 A

1/2.

 B

$\text"log"_3(6)$.

 C

$\text"log"_6(3)$.

 D

2.

Soln.
Ans: a

$\text"log"_6(729)$ is same as $\text"log"_6(3^6)$ = 6 × $\text"log"_6(3)$ = $6/{\text"log"_3(6)}$, which is same as $6/12$ = 1/2.


Question 2

What is log$7$ + log$1/7$?

 A

0.

 B

$\text"log"_3(7)$.

 C

$\text"log"_7(3)$.

 D

1/2.

Soln.
Ans: a

log(m) + log(1/m) = log (m × $1/m$) = log 1 = 0.


Question 3

What is the value of log(2) - log(1)?

 A

log($2/1$).

 B

log($1/2$).

 C

log2(1).

 D

log1(2).

Soln.
Ans: a

log($m/n$) = log(m) - log(n) always.


Question 4

What is x if logx$(6/7)$ = 1?

 A

${6/7}$.

 B

${36/49}$.

 C

$√{6/7}$.

 D

$√{7/6}$.

Soln.
Ans: a

logx$(6/7)$ = 1, by definition, gives $x^1$ = $6/7$. So x = ${6/7}$.


Question 5

Let us suppose that log(3) = 4, then what is log($1/30$) if the base is 10?

 A

-5.

 B

$\text"log"_4(30)$.

 C

$\text"log"_3(40)$.

 D

5.

Soln.
Ans: a

We know log($1/{10m}$) = log(1) - (log(10) + log(m)) = 0 - (1 + 4) = -5.


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This Blog Post/Article "Logarithms Quiz Set 007" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2019-08-18.

Posted by Parveen(Hoven),
Aptitude Trainer


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