Pipes and Cisterns Quiz Set 004 | Maths Aptitude Quiz Questions and Mock Test on Pipes and Cisterns Set 4 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

What is the volume of the tank in liters if it measures 5m × 9m × 8m?

360000 liters.

360 liters.

4050 liters.

20000 liters.

Soln.
Ans: a

The volume in m³ is 5 × 9 × 8 = 360m³. But 1m³ = 1000L. So volume in liters = 360 × 1000 = 360000L.

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Question 2

A city tanker is filled by two large pipes, X and Y, together in 18 and 12 minutes respectively. On a certain day, pipe Y is used for first half of the time, and both X and Y are used for the second half. How many minutes does it take to fill the tank?

9 mins.

10 mins.

8 mins.

11 mins.

Soln.
Ans: a

Let the time taken be x. Y is running for x mins, and X for x/2. So $(x/12 + x/{2 × 18})$ = 1. Solving for x, we get x = 9 mins.

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Question 3

Two pipes can together fill a cistern in 3 minutes. How long does the slower alone take if the speeds of the pipes are in the ratio 4 : 1?

15 mins.

16 mins.

14 mins.

17 mins.

Soln.
Ans: a

Let the time taken by the slower pipe alone be x. Then 3 × $(1/x + 4/x)$ = 1. Solving for x, we get x = 3 × 5 = 15 mins.

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Question 4

A tank is filled in $1{1/11}$ minutes by three taps running together. Times taken by the three taps to independently fill the tank are in an AP[Arithmetic Progression]. If the first tap is a leakage tap and the second tap takes 1 minute to fill the tank, then, the common difference of the AP can be?

Soln.
Ans: a

Let the times taken by the three taps be 1 - d, 1 and 1 + d. The time taken by the first tap will be negative because it is a leakage tap. Then ${12/11}$ minutes work of all the taps should add to 1. So we have, ${12/11}$ × $(1/{1 - d} + 1/1 + 1/{1 + d})$ = 1, which is same as $2/{1 - d^2} + 1$ = ${11/12}$. Solving we get d = ±5.

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Question 5

Three taps R, G and B are supplying red, green and blue colored inks into a tub. They can independently fill the tub in 6, 8 and 6 minutes. They are turned on at the same time. What is the ratio of blue ink after 3 minutes?

${4/11}$.

$1{1/2}$.

${4/13}$.

$2{11/13}$.

Soln.
Ans: a

Let the time taken by them to independently fill the tank be r, g and b minutes. Ink discharged by the blue tap is $3/b$. The total of all the inks is $3/r + 3/g + 3/b$. The ratio is ${1/b}/{1/r + 1/g + 1/b}$, which simplifies to ${rg}/{rg + gb + br}$ = ${4/11}$.

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