Probability Quiz Set 005

Advertisement


Your Score
Correct Answers:
Wrong Answers:
Unattempted:

Question 1

A box contains 5 maroon, 4 pink and 8 sky blue balls. What is the probability of drawing a ball that is neither pink nor maroon?

 A

${8/17}$.

 B

$9/17$.

 C

$9/136$.

 D

$13/136$.

Soln.
Ans: a

Total number of marbles is 17. We have to basically find the probability of picking a sky blue ball, for which 8 chances are favorable. So probability = 8/17 = ${8/17}$.


Question 2

9 bowls are lying inverted on a table. 2 of them contain prizes, but 7 of them are empty. What is the probability of getting a prize if one of the bowls is opened randomly?

 A

${2/9}$.

 B

$3/9$.

 C

$4/9$.

 D

$7/9$.

Soln.
Ans: a

Chances favoring a prize are 2, whereas the total chances are 9. The probability is 2/9 = ${2/9}$.


Question 3

A bag contains 2 Red, 8 Blue and 7 Green marbles. What is the probability of drawing a Red marble if 2 marbles are drawn out randomly?

 A

${31/136}$.

 B

$7/17$.

 C

$32/136$.

 D

$36/136$.

Soln.
Ans: a

Total number of marbles is 17. Combinations of 2 marbles that are possible = 17C2 = ${17 × 16}/2$ = 136. If one of the two balls is red, then red + red is one possibility, and 2 × (8 + 7) are the other possibilities. So total favorable outcomes = 1 + 2 × 15 = 31, and the probability is 31/136 = ${31/136}$.


Question 4

From a deck of 52 cards two cards are drawn at random. What is the probability that both will be "10"?

 A

${1/221}$.

 B

$9/15$.

 C

$2/221$.

 D

$6/221$.

Soln.
Ans: a

Number of ways of drawing 2 cards out of 52 = 52C2 = $(52 × 51)/2$ = 1326. There are 4 "10"s in all, so 2 can be drawn in 4C2 = $(4 × 3)/2 = 6$ ways. The probability is 6/1326 = ${1/221}$.


Question 5

A box contains 3 pink, 4 maroon and 6 orange marbles. What is the probability of drawing a orange marble if 2 marbles are drawn out randomly?

 A

${19/26}$.

 B

$6/13$.

 C

$20/78$.

 D

$24/78$.

Soln.
Ans: a

Total number of marbles is 13. Combinations of 2 marbles that are possible = 13C2 = ${13 × 12}/2$ = 78. If one of the two balls is orange, then both balls will be orange in 6C2 = ${6 × (6 - 1)}/2$ = 15 ways. The number of ways in which non-orange can be drawn out are 6 × (3 + 4). So total favorable outcomes = 15 + 6 × 7 = 57, and the probability is 57/78 = ${19/26}$.


buy aptitude video tutorials


Creative Commons License
This Blog Post/Article "Probability Quiz Set 005" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-06-24.

Posted by Parveen(Hoven),
Aptitude Trainer


Advertisement