Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

Each year the ages of three friends are in an AP(arithmetic progression). The age of middle friend today is 19 years. What would be the sum of their ages 10 years from now?

**A**

87 years.

**B**

88 years.

**C**

86 years.

**D**

89 years.

**Soln.**

**Ans: a**

Let the present ages of the three friends be a - d, a and a + d. As of today a = 19. Ten years later their ages would be a + 10 - d, a + 10, a + 10 + d. Adding these we get 3a + 30 which equals 3 × 19 + 30 = 87 years.

### Question 2

The sum of ages of two friends is 15, whereas the product of their ages is 54. What is the sum of squares of their ages?

### Question 3

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 120. What is the age of the middle friend today?

### Question 4

The sum of ages of two friends is 23, whereas the product of their ages is 126. What is the sum of squares of their ages?

### Question 5

The ages of two friends are in the ratio 11:19. What is the age of the younger friend if the sum of their ages is 90 years?

This Blog Post/Article "Problems on Ages Quiz Set 004" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-10-26.