Problems on Ages Quiz Set 007


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Question 1

My present age is 432 times the reciprocal of my age 6 years back. What is my present age?

 A

24 years.

 B

25 years.

 C

23 years.

 D

26 years.

Soln.
Ans: a

Let the present age be x. Then $x = 432/{x - 6}$. At this stage a better option is that you try putting the given answers into this expression one by one. The other option is to simplify this expression into a quadratic equation $x × (x - 6)$ = 432. This can now be solved to give x = 24 years.


Question 2

The ages of three friends are in the ratio 11:5:13. What is the age of the youngest friend if the sum of their ages is 116 years?

 A

20 years.

 B

21 years.

 C

19 years.

 D

22 years.

Soln.
Ans: a

Let the ages of three friends be 11r, 5r and 13r. The youngest of these is 5r. We have been given their sum. So (11 + 5 + 13)r = 116. Solving, we get r = 4. The youngest is 5 × 4 = 20 years.


Question 3

P is 13 years older than Q, and Q's age is 6 times the age of R. If the sum of their ages today is 117, then what is the age of Q?

 A

48 years.

 B

49 years.

 C

47 years.

 D

50 years.

Soln.
Ans: a

Let the age of R be x. Then the age of Q is 6x, and that of P is 6x + 13. Adding the three ages, (6x + 13) + 6x + x = 117. Solving, we get x = 8. So the age of Q is 6x = 48 years.


Question 4

The sum of reciprocals of my ages 6 years back and 6 years later is ${16/247}$. What is my present age?

 A

32 years.

 B

33 years.

 C

31 years.

 D

34 years.

Soln.
Ans: a

Let the present age be x. Then $1/{x + 6} + 1/{x - 6}$ = ${16/247}$. At this stage a better option is that you try putting the given answers into this expression one by one. The other option is to simplify this expression into a quadratic equation ${2x}/{x^2 - 36}$ = ${16/247}$. This can now be solved to give x = 32 years.


Question 5

P is 13 years older than Q, and Q's age is 7 times the age of R. If the sum of their ages today is 88, then what is the age of Q?

 A

35 years.

 B

36 years.

 C

34 years.

 D

37 years.

Soln.
Ans: a

Let the age of R be x. Then the age of Q is 7x, and that of P is 7x + 13. Adding the three ages, (7x + 13) + 7x + x = 88. Solving, we get x = 5. So the age of Q is 7x = 35 years.


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Updated on 2020-02-07. Published on: 2016-04-23

Posted by Parveen(Hoven),
Aptitude Trainer


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