Correct Answers: | |
Wrong Answers: | |
Unattempted: |
Question 1
My present age is 432 times the reciprocal of my age 6 years back. What is my present age?
24 years.
25 years.
23 years.
26 years.
Ans: a
Let the present age be x. Then $x = 432/{x - 6}$. At this stage a better option is that you try putting the given answers into this expression one by one. The other option is to simplify this expression into a quadratic equation $x × (x - 6)$ = 432. This can now be solved to give x = 24 years.
Question 2
The ages of three friends are in the ratio 11:5:13. What is the age of the youngest friend if the sum of their ages is 116 years?
Question 3
P is 13 years older than Q, and Q's age is 6 times the age of R. If the sum of their ages today is 117, then what is the age of Q?
Question 4
The sum of reciprocals of my ages 6 years back and 6 years later is ${16/247}$. What is my present age?
32 years.
33 years.
31 years.
34 years.
Ans: a
Let the present age be x. Then $1/{x + 6} + 1/{x - 6}$ = ${16/247}$. At this stage a better option is that you try putting the given answers into this expression one by one. The other option is to simplify this expression into a quadratic equation ${2x}/{x^2 - 36}$ = ${16/247}$. This can now be solved to give x = 32 years.
Question 5
P is 13 years older than Q, and Q's age is 7 times the age of R. If the sum of their ages today is 88, then what is the age of Q?
More Chapters | See All...
Mirror Images | Image Series | Missing Numbers | Volume and Surface Areas | Analogies | Boats and Streams | Percentages | Partnerships | Averages | Classification Test | More...
This Blog Post/Article "Problems on Ages Quiz Set 007" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2020-02-07. Published on: 2016-04-23