Problems on Ages Quiz Set 013

Question 1

2 years back the ratio of ages of X and Y was \$1{1/20}\$. The ratio of their ages 4 years from now would be \$1{1/26}\$. What is the present age of X?

A

23 years.

B

24 years.

C

22 years.

D

25 years.

Soln.
Ans: a

Let their present ages be x and y. Then \${x - 2}/{y - 2} = \$ \${21/20}\$, which is same as: \$1{1/20}\$. Similarly, \${x + 4}/{y + 4} = \$ \${27/26}\$, which is same as: \$1{1/26}\$. Solving these equations for x and y, we get y = 22, and x = 23 years as the answer.

Question 2

5 years back the ratio of ages of X and Y was 1. The ratio of their ages 2 years from now would be 1. What is the present age of X?

A

20 years.

B

21 years.

C

19 years.

D

22 years.

Soln.
Ans: a

Let their present ages be x and y. Then \${x - 5}/{y - 5} = \$ 1. Similarly, \${x + 2}/{y + 2} = \$ 1. Solving these equations for x and y, we get y = 20, and x = 20 years as the answer.

Question 3

The ages of two friends are in the ratio 3:5. What is the age of the younger friend if the sum of their ages is 24 years?

A

9 years.

B

10 years.

C

8 years.

D

11 years.

Soln.
Ans: a

Let the ages be 3r and 5r. The younger is 3r. We have been given their sum. So (3 + 5)r = 24. Solving, we get r = 3. The younger is 3 × 3 = 9 years.

Question 4

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 72. What is the age of the middle friend today?

A

19 years.

B

20 years.

C

18 years.

D

21 years.

Soln.
Ans: a

Let the ages after 5 years be a - d, a and a + d. The sum is given to us. So (a - d) + a + (a + d) = 3a = 72. We get a = 72/3 = 24. So, the age of the middle friend today is a - 5 = 19 years.

Question 5

Mr. X became a voter at the age of 18. He got married at the age of 32. What was his average age during these two points of his life?

A

25 years.

B

26 years.

C

24 years.

D

14 years.

Soln.
Ans: a

The average is simply \${18 + 32}/2\$ = 25 years. 