Problems on Ages Quiz Set 013 | Maths Aptitude Mock Test on Problems of Ages Set 13 | mock tests for Bank PO, SSB/SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

2 years back the ratio of ages of X and Y was $1{1/20}$. The ratio of their ages 4 years from now would be $1{1/26}$. What is the present age of X?

23 years.

24 years.

22 years.

25 years.

Soln.
Ans: a

Let their present ages be x and y. Then ${x - 2}/{y - 2} = $ ${21/20}$, which is same as: $1{1/20}$. Similarly, ${x + 4}/{y + 4} = $ ${27/26}$, which is same as: $1{1/26}$. Solving these equations for x and y, we get y = 22, and x = 23 years as the answer.

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Question 2

5 years back the ratio of ages of X and Y was 1. The ratio of their ages 2 years from now would be 1. What is the present age of X?

20 years.

21 years.

19 years.

22 years.

Soln.
Ans: a

Let their present ages be x and y. Then ${x - 5}/{y - 5} = $ 1. Similarly, ${x + 2}/{y + 2} = $ 1. Solving these equations for x and y, we get y = 20, and x = 20 years as the answer.

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Question 3

The ages of two friends are in the ratio 3:5. What is the age of the younger friend if the sum of their ages is 24 years?

9 years.

10 years.

8 years.

11 years.

Soln.
Ans: a

Let the ages be 3r and 5r. The younger is 3r. We have been given their sum. So (3 + 5)r = 24. Solving, we get r = 3. The younger is 3 × 3 = 9 years.

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Question 4

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 72. What is the age of the middle friend today?

19 years.

20 years.

18 years.

21 years.

Soln.
Ans: a

Let the ages after 5 years be a - d, a and a + d. The sum is given to us. So (a - d) + a + (a + d) = 3a = 72. We get a = 72/3 = 24. So, the age of the middle friend today is a - 5 = 19 years.

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