# Maths Aptitude Quiz Questions and Mock Test on Problems on Trains Set 19

## These are aptitude questions on Problems on Trains type of questions. You will need to have a basic understanding of speed and distance. This collection is more than sufficient for giving you practice on this topic. Go through this series if you are preparing for exams like the Bank PO, IBPS Specialist Officers, GATE, SSC, NTSE and similar exams that test your mental ability skills. This is quiz no. 19 in this series.

Last Reviewed and Updated on August 18, 2019

## Quiz Questions

Each question has four choices. More than one option can be correct. After you have finished the quiz scroll towards the last question to view your result. I have provided solutions and answers to all the questions.

### Question 1

A train is running at a speed of 68km/h. If it takes 72sec to move past a telegraph pole, then what is its length?

A

1359 meters.

B

1362 meters.

C

1360 meters.

D

1361 meters.

Soln.
Ans: C

The total distance to be covered is equal to the length of the train. By the time and distance formula, we get length = time × speed × (5/18), which gives \$72 × 68 × (5/18)\$ = 1360m. Please note that 5/18 is the conversion from km/h to m/s.

Question ID: 16-05-13-07-42-00-091.
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### Question 2

Two trains are moving in same direction on two parallel tracks. How many seconds will they take to cross each other if the sum of their lengths is 288m, and the difference of their speeds is 36m/s?

A

7 sec.

B

8 sec.

C

10 sec.

D

9 sec.

Soln.
Ans: B

The total distance is equal to the sum of the lengths of the trains, so s = 288. This distance has to be covered at a net relative speed equal to the difference of the speeds of the two trains, so v = 36. The time will be distance/speed = \$288/36\$ = 8s.

Question ID: 16-05-13-07-42-00-092.
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### Question 3

A train of length 129 m crosses a bridge at a speed of 60 km/h in 30 seconds. What is the length of the bridge?

A

6350 meters.

B

6352 meters.

C

6351 meters.

D

6353 meters.

Soln.
Ans: C

In 30 seconds the train covers a distance of 30 × 60 × (18/5) = 6480 meters. This distance is the sum of the lengths of the train and the bridge. Subtracting the length of the train we get the length of the bridge = 6480 - 129 = 6351 meters.

Question ID: 16-05-13-07-42-00-093.
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### Question 4

Two trains running in opposite directions cross each other in 28 seconds. They, respectively, take 17 and 68 seconds to cross a man standing on the platform. What is the ratio of their speeds?

A

\$1{4/13}\$.

B

\${11/40}\$.

C

\$3{5/42}\$.

D

\$2{1/6}\$.

Soln.
Ans: B

Let the ratio of their speeds by r. If the speed of one train is v, then the speed of the other is rv. By the speed and distance formula, the sum of their lengths is \$(v × 17) + (rv × 68)\$ which should equal the value obtained from the time they take to cross each other,i.e., \$(v + rv) × 28)\$. So \$v × (17 + r × 68\$ = \$v × (1 + r) × 28).\$ Cancelling v and solving for r we get \${11/40}\$.

Question ID: 16-05-13-07-42-00-094.
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### Question 5

A train speeding at 18 km/h crosses the platform in 45seconds, but it takes 9 seconds to cross a man standing on the same platform. What is the length of the train?

A

181 meters.

B

182 meters.

C

179 meters.

D

180 meters.

Soln.
Ans: D

The speed of the train in m/s is 18 × (5/18) = 5 m/s. The length of the train can be obtained from the time it takes to cross the man = \$5 × 9\$ = 45meters. The combined length of the train and platform can be obtained from the time it takes to cross the platform, = \$5 × 45 = 225\$ meters. Subtracting, we get the length of the train = 180 m.

Question ID: 16-05-13-07-42-00-095.
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