Ratio and Proportion Quiz Set 010 | Maths Aptitude Quiz Questions and Mock Test on Ratio and Proportion Set 10 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

What is the value of the first part if 160 is divided in the ratio $3/2$ : $3/2$ : $7/3$?

45.

49.

41.

53.

Soln.
Ans: a

We have $3/2$ : $3/2$ : $7/3$. Now 6 is the LCM of 2, 2 and 3, so the ratios become $3/2 × 6$ : $3/2 × 6$ : $7/3 × 6$, which are same as 9 : 9 : 14. The value of the first item is $9/{9 + 9 + 14}$ × 160 = 45.

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Question 2

Two numbers M and N are in ratio 13 : 9. If they are, respectively, increased by 60% and 30%, what will be the new ratio of M : N?

$1{7/9}$.

$3{1/8}$.

${7/11}$.

$3{10/11}$.

Soln.
Ans: a

New M will scale to $160/100$ × 13, and N to $130/100$ × 9. New ratio is ${160 × 13}/{130 × 9}$ = ${16/9}$, which is same as: $1{7/9}$.

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Question 3

A 350 liter mixture of milk and water contains 78% milk. How many more liters of water should be added so that the proportions of milk and water become equal?

196 liter.

197 liter.

195 liter.

199 liter.

Soln.
Ans: a

The volume of milk will remain same at ${78 × 350}/100$ = 273 liters. The amount of water at present is 350 - 273 = 77 liters. We need to make the volume of water equal to that of the milk. So we have to add 273 - 77 = 196 liters of water.

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Question 4

A mixture of milk and water contains 11 parts of milk and 9 parts of water. How much fraction of the mixture should be removed and replaced by water so that ratio of water and milk becomes equal?

${1/11}$.

$1{1/5}$.

$1{10/13}$.

$2{8/13}$.

Soln.
Ans: a

Let the volume of the mixture be 11 + 9 = 20 liters. If x liters of the mixture is removed and replaced by water, the volume of water in the new mixture is $9 - {9x}/20 + x$. The volume of the milk in the new mixture would be $11 - {11x}/20.$ Equating the two volumes and solving for x we get x = ${20 × 2}/{2 × 11}$. The fraction that must be removed = $1/20$ × ${20 × 2}/{2 × 11}$, which gives $2/{2 × 11}$ = ${1/11}$.

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Question 5

If 50% of a number is equal to 2/7 of another number, then what is the ratio of first number to second number?

${4/7}$.

$1{5/6}$.

$2{7/9}$.

Soln.
Ans: a

We have ${50A}/100 = {2B}/7$, which can be re-arranged to $A/{2 × 100} = B/{50 × 7}$, so the required ratio is (2 × 100) : (50 × 7), which is 4 : 7. So the answer is ${4/7}$.

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