Ratio and Proportion Quiz Set 020


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Question 1

If X is 70% more than Z, and Y is 50% more than Z, what is the ratio of X to Y?

 A

$1{2/15}$.

 B

$2{2/7}$.

 C

${2/17}$.

 D

$3{11/17}$.

Soln.
Ans: a

Clearly, X = $(100 + 70)/100$ × Z, and Y = $(100 + 50)/100$ × Z, which gives X : Y as $(100 + 70)/(100 + 50)$ = $170/150$ = ${17/15}$, which is same as: $1{2/15}$


Question 2

A mixture of milk and water contains 43 parts of milk and 9 parts of water. How much fraction of the mixture should be removed and replaced by water so that ratio of water and milk becomes equal?

 A

${17/43}$.

 B

$1{3/7}$.

 C

$2{13/45}$.

 D

$3{11/45}$.

Soln.
Ans: a

Let the volume of the mixture be 43 + 9 = 52 liters. If x liters of the mixture is removed and replaced by water, the volume of water in the new mixture is $9 - {9x}/52 + x$. The volume of the milk in the new mixture would be $43 - {43x}/52.$ Equating the two volumes and solving for x we get x = ${52 × 34}/{2 × 43}$. The fraction that must be removed = $1/52$ × ${52 × 34}/{2 × 43}$, which gives $34/{2 × 43}$ = ${17/43}$.


Question 3

A mixture of milk and water contains 14 parts of milk and 1 parts of water. How much fraction of the mixture should be removed and replaced by water so that ratio of water and milk becomes equal?

 A

${13/28}$.

 B

$1{14/27}$.

 C

$2{3/10}$.

 D

$3{7/30}$.

Soln.
Ans: a

Let the volume of the mixture be 14 + 1 = 15 liters. If x liters of the mixture is removed and replaced by water, the volume of water in the new mixture is $1 - {1x}/15 + x$. The volume of the milk in the new mixture would be $14 - {14x}/15.$ Equating the two volumes and solving for x we get x = ${15 × 13}/{2 × 14}$. The fraction that must be removed = $1/15$ × ${15 × 13}/{2 × 14}$, which gives $13/{2 × 14}$ = ${13/28}$.


Question 4

If a : b is 17 : 9, then what is (4a - 3b) : (7a - 8b)?

 A

${41/47}$.

 B

$1{21/23}$.

 C

$2{37/49}$.

 D

$3{5/7}$.

Soln.
Ans: a

Simply substitute the values to get (4a - 3b) : (7a - 8b) as (4 × 17 - 3 × 9) : (7 × 17 - 8 × 9) = $41/47$ = ${41/47}$.


Question 5

The sides of a triangle are in the ratio 2 : 14 : 13, which is the longest side, if the perimeter is 580?

 A

280.

 B

282.

 C

278.

 D

284.

Soln.
Ans: a

Let the sides be 2x, 14x and 13x. We have 2x + 14x + 13x = 580, or 29x = 580, which gives x = 20, so the longest side is 14 × x = 14 × 20 = 280.


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Updated on 2020-02-07. Published on: 2016-05-12

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