Question 13 SSC-CGL 2018 June 4
[NOTE: only math questions solved]
Question: A circle is drawn inside a triangle ABC. The circle touches the sides AB, BC and AC at the points R, P and Q respectively. If AQ = 4.5 cm, PC = 5.5 cm and BR = 6 cm, then the perimeter of triangle ABC is:
- 32 cm
- 28 cm
- 30.5 cm
- 26.5 cm
Method 1
Use the theorem that tangents to a circle from an external point are equal in length.
Observe that AR and AQ will be equal tangents measuring 4.5 cm each. Similarly, CQ and CP each = 5.5 cm. And BR and BP each equal to 6 cm.
Adding all the above lengths, perimeter is 4.5x2 + 5.5x2 + 6x2 = 32 cm Ans!
Any other method? Let me know in the comments.
This Blog Post/Article "Question 13 SSC CGL 2018 June 4 Shift 1" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2020-02-07. Published on: 2020-02-02