Question 8 SSC-CGL 2018 June 4
[NOTE: only math questions solved]
Question: An amount becomes 8,028 in 3 years at a fixed percentage interest rate and 12,042 in 6 years, when the interest is compounded annually. What is the actual amount?
- 5352
- 5235
- 5253
- 5325
Method 1
Periods of growth are 3 year each, so we can apply unitary method.
Observe that Re. 12042 is obtained from 8028 in three years.
By unitary, Re. 1 will be obtained from $\displaystyle \frac{8028}{12042}$
Hence, Re. 8028 was obtained from $\displaystyle \frac{8028}{12042} \times 8028$ = $\displaystyle 5352$ Ans.
Method 2
By CI formula, $\displaystyle 8028 = P \bigg(1 + r\bigg)^3 \text{ . . . (1)}$
also given, $\displaystyle 12042 = P \bigg(1 + r\bigg)^6\text{ . . . (2)}$
Squaring (1), then dividing by (2), $\displaystyle P = \frac{8028 \times 8028}{12042} = 2 \times \text{something}$
Either calculate or conclude that P must be even. Hence (a) is the answer!
Method 3
In compound interest, percent growth is same for same periods of time.
$\displaystyle P \xrightarrow [\text{3 yrs}]{\times 1.5} 8028 \xrightarrow [\text{3 yrs}]{\times 1.5} 12042$
Hence P must be $\displaystyle \frac{2}{3} \times 8028= 5352$. Hence (a) is the answer!
This Blog Post/Article "Question 8 SSC CGL 2018 June 4 Shift 1" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2020-02-07. Published on: 2020-01-21