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### Question 1

Each box of a almirah has as many balls as is the total number of boxes in that almirah. If there are 144 balls in all, how many boxes are there?

### Question 2

If $√2$ = 1.41, then what is the value of ${√2}/5$ − $2/{√2}$ + $√8$?

**A**

1.697.

**B**

1.414.

**C**

1.732.

**D**

0.707.

**Soln.**

**Ans: a**

The given expression can be simplified to ${{(√2)^2} - {5 × 2} + {5 × √2 × √{2 × 2^2}}}/{5 × √2}$, which is same as ${2 - 10 + 20}/{5 × √2}$, which is same as ${12/{5 × √2}$. Rationalizing, we get ${12/{5 × √2} × {√2/√2}$ which gives ${12√2}/10$ which = 1.697.

### Question 3

If $√5$ = 2.24, then what is the value of ${√5}/2$ − $3/{√5}$ + $√20$?

**A**

4.249.

**B**

4.449.

**C**

4.649.

**D**

4.496.

**Soln.**

**Ans: a**

The given expression can be simplified to ${{(√5)^2} - {2 × 3} + {2 × √5 × √{5 × 2^2}}}/{2 × √5}$, which is same as ${5 - 6 + 20}/{2 × √5}$, which is same as ${19/{2 × √5}$. Rationalizing, we get ${19/{2 × √5} × {√5/√5}$ which gives ${19√5}/10$ which = 4.249.

### Question 4

What is the value of ${√11}/3$ − $2/{√11}$?

**A**

${5√11}/33$.

**B**

${15√11}/33$.

**C**

${13√11}/33$.

**D**

${6√11}/33$.

**Soln.**

**Ans: a**

The given expression can be simplified to ${{(√11)^2} - 3 × 2}/{3 × √11}$, which is same as ${11 - 6}/{3 × √11}$, which is same as ${5/{3 × √11}$. Rationalizing, we get ${5/{3 × √11} × {√11/√11}$ which gives ${5√11}/33$

### Question 5

If $√2$ = 1.41, then what is the value of ${√2}/5$ − $5/{√2}$ + $√50$?

**A**

3.818.

**B**

-3.818.

**C**

7.636.

**D**

-7.636.

**Soln.**

**Ans: a**

The given expression can be simplified to ${{(√2)^2} - {5 × 5} + {5 × √2 × √{2 × 5^2}}}/{5 × √2}$, which is same as ${2 - 25 + 50}/{5 × √2}$, which is same as ${27/{5 × √2}$. Rationalizing, we get ${27/{5 × √2} × {√2/√2}$ which gives ${27√2}/10$ which = 3.818.

This Blog Post/Article "Square and Cube Roots Quiz Set 003" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2020-02-07. Published on: 2016-04-20