Time and Work Quiz Set 007

If m₁ men can do a task in d₁ days by working h₁ hours per day, and m₂ in d₂ days by working h₂ hours per day, then we must have m₁ × d₁ × h₁ = m₂ × d₂ × h₂. Putting m₁ = 30, d₁ = 54, h₁ = 12, d₂ = 10, and h₂ = 9 we get m₂ = 216.

If m₁ men can do a task in d₁ days, and m₂ in d₂, then we must have m₁ × d₁ = m₂ × d₂. Putting m₁ = 56, d₁ = 16 and d₂ = 7, we get m₂ = 128.

Let us first calculate the one day work of B. One day work of A is given as $1/11$. If B is 10% efficient, then one day work of B is $1/11$ × $110/100$ = $1/10$. Which gives 10 days as the answer.

One day work of A + B is $1/49$. One day work of A is $1/56$. So one day work of B, say, $1/y$ = $1/49$ - $1/56$. Solving, we get y = 392 days.

Work done by A in 1 day = $1/10$. So the work in 2 days = 2 × $1/10$. His share is Rs. 2 × $1/10$ × 7000 = Rs. 1400.