Question
Two trains start simultaneously from two stations separated by 560 km. Their speeds are 30 km/h and 40 km/h. Just at the time when they started, a bird that was sitting on the engine of one of them, began to fly towards the other train. On reaching that train, the bird started to fly to and fro towards the first train, and kept doing so till it was crushed. How much distance was travelled by the bird, if it was travelling at 90 km/h [Bank Exam 1989]?
Solution
Time taken by the trains to meet = $560/{30 + 40} = 8$ hours. Distance travelled by the bird in 8 hours = speed × time = 90 × 8 = 720 km.
The detailed solution of the above problem is contained inside this video. Since many other questions are also contained in this, you might have to search a bit in this video.