HCF and LCM Quiz Set 004 | Maths Aptitude Quiz Questions and Mock Test on HCF and LCM Set 4 | mock tests for Bank PO, SSB/SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

The sum of LCM and HCF of two numbers is 420. If LCM is 83 times the HCF, then the product of the two numbers is?

2075.

2077.

2076.

2078.

Soln.
Ans: a

Let L be the LCM, and H the HCF. Then H + L = 420, and L = 83H. Solving these for H, we get H = $420/{83 + 1}$ = 5, and L = 415. The product of the two numbers is equal to the product of the lcm and hcf = 5 × 415 = 2075.

Solution | Discuss! | Chapters»

Question 2

The HCF of two numbers is 41. The factors of their LCM are 41, 29 and 13. Which is the greater of the two numbers?

1189.

2378.

594.

3567.

Soln.
Ans: a

The numbers are 41 × 29 = 1189, and 41 × 13 = 533. The greater of them is 1189.

Solution | Discuss! | Chapters»

Question 3

What is the LCM of 57, 24 and 81?

12312.

24624.

6156.

36936.

Soln.
Ans: a

The required LCM = 12312.

Solution | Discuss! | Chapters»

Question 4

Which is the least number which must be added to 7347 so that it becomes divisible by 21, 75 and 98?

Soln.
Ans: a

The LCM of 21, 75 and 98 = 7350. The lcm when divided by either of these numbers leaves the remainder 0. The minimum number to be added is 7350 - 7347 = 3.

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Question 5

What is the HCF of (8 × 7), (7 × 16) and (16 × 8)?

16.

24.

Soln.
Ans: a

The required HCF is product of the three numbers divided by their LCM. The LCM of 8, 7 and 16 is 112. So the required HCF = ${8 × 7 × 16}/112$ = 8. Please note that LCM(n1, n2, n3) × HCF(n1 × n2, n2 × n3, n3 × n1) = n1 × n2 × n3.

Solution | Discuss! | Chapters»