Problems on Numbers Quiz Set 003

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Question 1

x should be replaced by which minimum number so that 4618521x98 is completely divisible by 3?

 A

1.

 B

2.

 C

4.

 D

3.

Soln.
Ans: a

If the above number has to be divisible by 3, the sum of the digits, i.e., 4 + 6 + 1 + 8 + 5 + 2 + 1 + x + 9 + 8, should be divisible by 3. So we can see that $x + 44$ should be divisible by 3. By inspection, x = 1.


Question 2

12 times the middle of three consecutive even numbers is 152 more than 8 times the smallest of the three numbers. What is the middle number?

 A

34.

 B

35.

 C

33.

 D

36.

Soln.
Ans: a

This is the general solution. Let the numbers be 2n - 2, 2n and 2n + 2. We are given 12 × 2n = 152 + 8 × (2n - 2).
⇒ 12 × 2n = 152 + 8 × 2n - 8 × 2.
⇒ 2n × (12 - 8) = 152 - 8 × 2, so 2n = ${152 - 8 × 2}/{12 - 8} = 34$


Question 3

Which term of this arithmetic series is zero: 110, 100, 90 ...?

 A

12.

 B

13.

 C

11.

 D

14.

Soln.
Ans: a

The first term is 110, common difference is d = -10, n-th term is 0. So $0 = 110 + (n - 1) × -10$ which gives $n = 1 + {110/10} = 12$.


Question 4

The sum of three consecutive odd integer numbers is 909. The middle among the three is?

 A

303.

 B

304.

 C

302.

 D

305.

Soln.
Ans: a

Let the numbers be 2n - 3, 2n - 1 and 2n + 1. The sum is 3(2n - 1) = 3 x middle. We are given 3 x middle = 909, ⇒ middle = $909/3$, i.e., middle = 303.


Question 5

What is 0.94949494...?

 A

$94/99$.

 B

$95/99$.

 C

$94/100$.

 D

$94/101$.

Soln.
Ans: a

0.94949494... is same as $0.\ov 94$. Let y = $0.\ov 94$. Multiply by 100, 100y = 94 + $0.\ov 94$ which is same as 94 + y. So 99y = 94, ⇒ y = $94/99$. So answer = ${94/99}$.


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This Blog Post/Article "Problems on Numbers Quiz Set 003" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-06-22.

Posted by Parveen(Hoven),
Aptitude Trainer


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