Maths Aptitude Quiz Questions and Mock Test on Problems on Trains Set 18

These are aptitude questions on Problems on Trains type of questions. You will need to have a basic understanding of speed and distance. This collection is more than sufficient for giving you practice on this topic. Go through this series if you are preparing for exams like the Bank PO, IBPS Specialist Officers, GATE, SSC, NTSE and similar exams that test your mental ability skills. This is quiz no. 18 in this series.

Last Reviewed and Updated on June 24, 2017
Posted by Parveen(Hoven),
Aptitude Trainer and Software Developer

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Quiz Questions

Each question has four choices. More than one option can be correct. After you have finished the quiz scroll towards the last question to view your result. I have provided solutions and answers to all the questions.


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Question 1

A train 936 meters long is moving at a speed of 72m/s. How long will it take to cross a man who is running in the opposite direction at a speed of 84m/s?

 A

8 sec.

 B

7 sec.

 C

5 sec.

 D

6 sec.

Soln.
Ans: D

The distance to be covered is equal to the length of the train, so s = 936. This distance has to be covered at a net relative speed equal to the sums of the speeds of the man and the train, so v = 72 + 84 = 156. The time will be distance/speed = $936/156$ = 6 s.

Question ID: 16-05-13-07-42-00-086.
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Question 2

A train running at a speed of 17m/s crosses a pole in 13sec. How long will it take to cross a platform of length 1105m?

 A

78 sec.

 B

79 sec.

 C

77 sec.

 D

80 sec.

Soln.
Ans: A

The length of the train can be obtained from the time it takes to cross the pole. The length of the train = $17 × 13$ = 221m. To cross the platform it must travel a total distance equal to the combined lengths of the train and the platform at this speed. So time = ${221 + 1105}/17$ = 78 seconds.

Question ID: 16-05-13-07-42-00-087.
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Question 3

A train passes two persons walking in the same direction as the train. The time it takes to move past the man running at 4km/h is 6sec, whereas the time it takes to cross the other man running at 11km/h is 7sec. What is the speed of the train?

 A

52 km/h.

 B

54 km/h.

 C

53 km/h.

 D

55 km/h.

Soln.
Ans: C

Let the speed of the train be v km/h. Length of the train calculated with the data for the first man = $(v - 4) × 6$. It should equal the length obtained from the data for the second man. So $(v - 4) × 6$ = $(v - 11) × 7$. Please note that we have not converted seconds to hours because that factor will ultimately cancel away. Solving for v we get 53km/h.

Question ID: 16-05-13-07-42-00-088.
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Question 4

A train running at 10km/h leaves a railway station 45 hours later than another train, and meets it in 5 hours. What is the speed of the other train?

 A

2 km/h.

 B

4 km/h.

 C

3 km/h.

 D

1 km/h.

Soln.
Ans: D

Let the speed of the train be v km/h. Distance travelled by this train in (5 + 45) hours = 50v km. Equating this to the distance travelled by the second train we get 50v = 10 × 5, which gives v = 1 km/h.

Question ID: 16-05-13-07-42-00-089.
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Question 5

Two trains moving in the same direction, and running respectively at 72km/h and 144km/h cross each other in 5sec. What is the length of each train if the two trains are equally long?

 A

50 m.

 B

52 m.

 C

51 m.

 D

49 m.

Soln.
Ans: A

The trains cover a distance equal to the sum of their lengths at a relative speed 144 - 72 = 72km/h × (5/18), or 20m/s. We can use the speed distance formula: sum of lengths = 20 × 5 = 100m. Halving this we get the length of one train = 50m.

Question ID: 16-05-13-07-42-00-090.
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This Blog Post/Article "Maths Aptitude Quiz Questions and Mock Test on Problems on Trains Set 18" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-06-24.


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