Alphabet Number Series Quiz Set 172


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Question 1

If the alphabets at the positions 5, 18, 20 and 25 are picked up and a meaningful word is formed out of them, what would be the second letter of that word?

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

 A

Y

 B

T

 C

R

 D

B

Soln.
Ans: a

The letters are: E, R, T, Y. The word is TYRE


Question 2

In the following series which item is 5th to the left of the 9th item from the right side? The series is:

R H E M 2 T 1 9 X F B V 7 G + J S % L U

 A

1

 B

V

 C

G

 D

7

Soln.
Ans: a

We have to find 9 + 5 = 14th item from the right side which is: 1.


Question 3

If every letter beginning from I is replaced by consecutive odd number beginning with 3, which number or letter will be 4th to the right of the 15th number or letter counting from the right end?

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

 A

17

 B

D

 C

37

 D

5

Soln.
Ans: a

The series becomes:

A B C D E F G H 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37


Question 4

If an item is at position 13 from the top of a list and at position 19 from the bottom of that list, how many items are there in the list?

 A

31

 B

37

 C

28

 D

30

Soln.
Ans: a

Sum of positions of an item from top and bottom of a list is always equal to the sum of the positions of the first and last items. So total number of items is= position of last item is= 13 + 19 - 1 = 31.


Question 5

If an item is at position 18 from the top of a list and at position 9 from the bottom of that list, how many items are there in the list?

 A

26

 B

33

 C

23

 D

25

Soln.
Ans: a

Sum of positions of an item from top and bottom of a list is always equal to the sum of the positions of the first and last items. So total number of items is= position of last item is= 18 + 9 - 1 = 26.


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This Blog Post/Article "Alphabet Number Series Quiz Set 172" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2020-02-07. Published on: 2016-02-10

Posted by Parveen(Hoven),
Aptitude Trainer


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