Alphabet Number Series Quiz Set 217

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Question 1

In the number series written below, how many 9 are there that are completely divisible by both the two successors to their right?

6 4 6 9 7 2 9 5 2 8 1 8 9 9 9 7 9 4 8

 A

0

 B

3

 C

2

 D

1

Soln.
Ans: d

At these locations: 9-9-9 ;


Question 2

If the alphabets at the positions 5, 6, 14, 15, 18, 20 and 21 are picked up and a meaningful word is formed out of them, what would be the second letter of that word?

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

 A

O

 B

F

 C

R

 D

T

Soln.
Ans: a

The letters are: E, F, N, O, R, T, U. The word is FORTUNE


Question 3

If every letter beginning from position 14, counted from left, is replaced by H, how many H will be there in the resulting sequence?

C M E R U X W W D J M J R V Z H J O F G Q C I O I

 A

12

 B

6

 C

5

 D

1

Soln.
Ans: a

The series becomes:

C M E R U X W W D J M J R H H H H H H H H H H H H


Question 4

If the second half of the following series is reversed, then which item is 7th to the left of the 8th item from the right side? The series is:

T B E U 3 X F $ + Y O R 2 J 7 1 L Z W 8

 A

J

 B

X

 C

3

 D

B

Soln.
Ans: b

Midpoint is 10. We have to find 20 - 8 - 7 = 5 + 1th item from the left side. Since the location lies in the left half, reversing the series has no effect in this zone. So counting from the left side, the item is X.


Question 5

In the following series which item is 6th to the left of the 12th item from the right side? The series is:

O S X K R L 4 T U J 9 Q @ E $ 8 3 5 A B

 A

3

 B

X

 C

R

 D

B

Soln.
Ans: b

We have to find 12 + 6 = 18th item from the right side which is: X.


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Creative Commons License
This Blog Post/Article "Alphabet Number Series Quiz Set 217" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2019-08-18.

Posted by Parveen(Hoven),
Aptitude Trainer


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