# Ratio and Proportion Quiz Set 001

 Correct Answers: Wrong Answers: Unattempted:

### Question 1

A sum of Rs. 24000 is to be divided among three partners, P, Q and R, in the ratio 17 : 10 : 3. What is the difference between the shares of P and Q?

A

Rs. 5600.

B

Rs. 5602.

C

Rs. 5598.

D

Rs. 5604.

Soln.
Ans: a

The difference of shares of Q is in the ratio like this: \${17 - 10}/{17 + 10 + 3} × 24000\$ = Rs. 5600.

### Question 2

A 400 liter mixture of milk and water contains 86% milk. How many more liters of water should be added so that the proportions of milk and water become equal?

A

288 liter.

B

289 liter.

C

287 liter.

D

291 liter.

Soln.
Ans: a

The volume of milk will remain same at \${86 × 400}/100\$ = 344 liters. The amount of water at present is 400 - 344 = 56 liters. We need to make the volume of water equal to that of the milk. So we have to add 344 - 56 = 288 liters of water.

### Question 3

The ratio of shares of three friends in Rs. 2100 are in an A.P.(arithmtic progression). What is the share of the friend who is neither the richest, nor the poorest?

A

Rs. 700.

B

Rs. 704.

C

Rs. 696.

D

Rs. 708.

Soln.
Ans: a

Let the shares be in the ratio a - d : a : a + d. The value of the middle item is \$a/{(a - d) + a + (a + d)}\$ × 2100 = \$a/{3a}\$ × 2100 = \$2100/3\$ = Rs. 700.

### Question 4

Two numbers M and N are in ratio 17 : 7. If they are, respectively, increased by 50% and 10%, what will be the new ratio of M : N?

A

\$3{24/77}\$.

B

\$4{7/19}\$.

C

\$2{20/79}\$.

D

\$6{12/79}\$.

Soln.
Ans: a

New M will scale to \$150/100\$ × 17, and N to \$110/100\$ × 7. New ratio is \${150 × 17}/{110 × 7}\$ = \${255/77}\$, which is same as: \$3{24/77}\$.

### Question 5

A bag contains 25p, 10p and 5p coins in the ratio 2 : 13 : 12. How many 25 paise coins are there if the total amount is Rs. 48?

A

40.

B

42.

C

38.

D

44.

Soln.
Ans: a

Let the total number of coins be 2x, 13x and 12x. Please note that 25p = Rs. 1/4, 10p = Rs. 1/10, 5p = Rs. 1/20, so they add to x × \$(2/4 + 13/10 + 12/20)\$ = 48. LCM of 4, 10 and 20 is 20, multiplying both sides by 20 we have x × \$(2 × 5 + 13 × 2 + 12)\$ = 48 × 20, which is x × \$(10 + 26 + 12)\$ = 48 × 20, solving for x we get x = 20, so 25p coins = 20 × 2 = 40.

This Blog Post/Article "Ratio and Proportion Quiz Set 001" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2020-02-07. Published on: 2016-05-12

Posted by Parveen(Hoven),
Aptitude Trainer