Percentages Quiz Set 017 | Maths Aptitude Quiz Questions and Mock Test on Percentages Set 17 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

A clerk multiplied a number by 5/1 instead of 1/5. What is the percentage of error?

96 %.

98 %.

94 %.

100 %.

Soln.
Ans: a

If the actual figure is x, the error is ${5x}/1$ - ${1x}/5$ = ${5^2x - 1^2x}/{5 × 1}$ = ${24x}/5$, so %-error = ${(24x)/5}/{(5x)/1}$ × 100 = ${24 × 1}/{5 × 5}$ × 100 = 96%.

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Question 2

The number of online customers increased from 1850 to 3975. What is the percentage increase?

$114{32/37}$ %.

$119{1/12}$ %.

$108{1/39}$ %.

$111{32/39}$ %.

Soln.
Ans: a

The increase is 3975 - 1850 = 2125. The percentage increase is $2125/1850$ × 100 = ${4250/37}$, which is same as: $114{32/37}$.

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Question 3

If 11% of A + B = 18% of A - B, then what percent of B is A?

$4{1/7}$ %.

6 %.

$2{4/9}$ %.

$5{5/9}$ %.

Soln.
Ans: a

We have been given 11% of A + B = 18% of A - B, so ${A + B}/{A - B}$ = $18/11$. By componendo and dividendo, ${(A + B) + (A - B)}/{(A + B) - (A - B)}$ = ${18 + 11}/{18 - 11}$, which gives $A/B$ = $29/7$ = ${29/7}$, which is same as: $4{1/7}$%

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Question 4

Price of sugar is increased by 20%. By what percentage should consumption be reduced so that the expenditure remains same?

$16{2/3}$ %.

$26{1/2}$ %.

$15{2/3}$ %.

$11{4/5}$ %.

Soln.
Ans: a

Let price be Rs. 100/kg and the consumption be 1 kg. The current expenditure is 100 × 1 = Rs. 100. The new price of sugar is 100 + 20 = Rs. 120/kg. Let the new consumption be c kg. Now, if expenditure is to be same we should have 100 = 120 × c, which gives c = 100/120, so the decrease is 1 - $100/120$ = ${120 - 100}/120$ × 100% = ${50/3}$, which is same as: $16{2/3}$%.

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Question 5

If 17% of X + 8% of Y equals 2/3 of the sum of 4% of X and 15% of Y, then the ratio of X to Y is?

${6/43}$.

$1{1/6}$.

$2{2/45}$.

Soln.
Ans: a

We can drop the % from both sides and write the given equation as 17X + 8Y = $2/3$ × (4X + 15Y), which is same as 3 × (17X + 8Y) = 2 × (4X + 15Y). Let r = X/Y. Dividing both sides by Y and putting r = X/Y, we get, 3 × (17r + 8) = 2 × (4r + 15), solving for r we get r = ${6/43}$.

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