# Percentages Quiz Set 016

### Question 1

The number of online customers increased from 1850 to 3575. What is the percentage increase?

A

\$93{9/37}\$ %.

B

\$96{31/36}\$ %.

C

\$87{20/39}\$ %.

D

\$91{4/13}\$ %.

Soln.
Ans: a

The increase is 3575 - 1850 = 1725. The percentage increase is \$1725/1850\$ × 100 = \${3450/37}\$, which is same as: \$93{9/37}\$.

### Question 2

A sample of alcohol has 60% water, and another sample has 80% water. If equal volumes of both the samples are combined, what is the percentage of water in the new sample?

A

70 %.

B

72 %.

C

68 %.

D

74 %.

Soln.
Ans: a

If 100 units of both alcohol are combined, there will be 140 units of water in 200 units of the new sample. The percentage of water is \$140/200\$ × 100 = 70%.

### Question 3

The sum of two numbers is 1610. One of them is 130% of the other. The smaller number is?

A

700.

B

710.

C

690.

D

720.

Soln.
Ans: a

Let the numbers be x and \${130x}/100\$. The sum is x + \${130x}/100\$ which is same as \${230x}/100 = 1610\$. Solving we get the smaller number x = 700.

### Question 4

If 7% of A + B = 11% of A - B, then what percent of B is A?

A

\$4{1/2}\$ %.

B

\$5{1/2}\$ %.

C

\$3{1/2}\$ %.

D

\$3{3/4}\$ %.

Soln.
Ans: a

We have been given 7% of A + B = 11% of A - B, so \${A + B}/{A - B}\$ = \$11/7\$. By componendo and dividendo, \${(A + B) + (A - B)}/{(A + B) - (A - B)}\$ = \${11 + 7}/{11 - 7}\$, which gives \$A/B\$ = \$18/4\$ = \${9/2}\$, which is same as: \$4{1/2}\$%

### Question 5

A shopkeeper sells 83% items of his stock and still has 34 items left with him. How many items did he have at the beginning?

A

200 items.

B

300 items.

C

500 items.

D

400 items.

Soln.
Ans: a

Let the items be x. His % stock left is 100 - 83 = 17, so 17% of x = 34, which gives x = \$34/17\$ × 100 = 200 items. 