Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

What is the value of ^{7}C_{2}?

### Question 2

The letters of the word 'PERIOD' have to be arranged such that the vowels occupy only the odd positions. How many different ways are possible?

**A**

36.

**B**

46.

**C**

26.

**D**

56.

**Soln.**

**Ans: a**

This word has 6 letters, out of which 3 are consonants and 3 are vowels. The vowels have to occupy three fixed odd positions. We can place 3 vowels in first odd place, 2 in second odd place and 1 in the third odd place, giving 3 × 2 × 1 = 6 permutations. This will be done with the consonants also. So the total possibilities are 6 × 6 = 36.

### Question 3

In how many ways can 3 letter words be formed by using a given set of 6 consonants?

### Question 4

The letters of the word 'HOLIDAY' have to be arranged such that the vowels come together. How many different ways are possible?

**A**

720.

**B**

730.

**C**

710.

**D**

740.

**Soln.**

**Ans: a**

This word has 7 letters, out of which 4 are consonants and 3 are vowels. The vowels have to occupy three contiguous positions. This triad can be arranged in 3! ways like this: we can place 3 vowels in first place, 2 in second place and 1 in the third place, giving 3 × 2 × 1 = 6 permutations. Next, we have to arrange the 4 consonants and the triad treated as one letter, giving 5! = 120 possibilities. So the total possibilities are 6 × 120 = 720.

### Question 5

In how many ways can 4 prizes be given to 3 students if each of them is equally eligible?

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This Blog Post/Article "Permutations and Combinations Quiz Set 011" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-10-26.