Permutations and Combinations Quiz Set 012

Advertisement


Your Score
Correct Answers:
Wrong Answers:
Unattempted:

Question 1

How many 3 digit numbers can be formed with a given set of 5 distinct digits?

 A

125.

 B

135.

 C

155.

 D

145.

Soln.
Ans: a

The first place has 5 options, the second place also has 5 options, and so on. This is expressed as 5 × 5 × 5, which evaluates to 125.


Question 2

Out of given 8 consonants and 4 vowels, how many words can be formed that contain 3 consonants and 2 vowels or 3 vowels and 2 consonants?

 A

53760.

 B

53770.

 C

53750.

 D

53780.

Soln.
Ans: a

We can make the selection in 4C3 × 8C2 + 4C2 × 8C3 ways. But the five members can themselves be arranged in 5! ways. So the number of words is 120 × (4C3 × 8C2 + 4C2 × 8C3) = 53760.


Question 3

From a group of 7 men and 4 women, in how many ways can 3 men and 2 women or 2 men and 3 women be selected?

 A

294.

 B

304.

 C

284.

 D

314.

Soln.
Ans: a

The required count is 4C3 × 7C2 + 4C2 × 7C3 = 294.


Question 4

What is the value of 6P3?

 A

120.

 B

130.

 C

110.

 D

140.

Soln.
Ans: a

6P3 is ${6 !}/{(6 - 3) !}$ = 120.


Question 5

Out of given 7 consonants and 3 vowels, how many words can be formed that contain 3 consonants and 2 vowels or 3 vowels and 2 consonants?

 A

15120.

 B

15130.

 C

15110.

 D

15140.

Soln.
Ans: a

We can make the selection in 3C3 × 7C2 + 3C2 × 7C3 ways. But the five members can themselves be arranged in 5! ways. So the number of words is 120 × (3C3 × 7C2 + 3C2 × 7C3) = 15120.


buy aptitude video tutorials


Creative Commons License
This Blog Post/Article "Permutations and Combinations Quiz Set 012" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2019-08-18.

Posted by Parveen(Hoven),
Aptitude Trainer


Advertisement