Permutations and Combinations Quiz Set 012 | Maths Aptitude Quiz Questions and Mock Test on Permutations and Combinations Set 12 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

How many 3 digit numbers can be formed with a given set of 5 distinct digits?

125.

135.

155.

145.

Soln.
Ans: a

The first place has 5 options, the second place also has 5 options, and so on. This is expressed as 5 × 5 × 5, which evaluates to 125.

Solution | Discuss! | Chapters»

Question 2

Out of given 8 consonants and 4 vowels, how many words can be formed that contain 3 consonants and 2 vowels or 3 vowels and 2 consonants?

53760.

53770.

53750.

53780.

Soln.
Ans: a

We can make the selection in ⁴C₃ × ⁸C₂ + ⁴C₂ × ⁸C₃ ways. But the five members can themselves be arranged in 5! ways. So the number of words is 120 × (⁴C₃ × ⁸C₂ + ⁴C₂ × ⁸C₃) = 53760.

Solution | Discuss! | Chapters»

Question 3

From a group of 7 men and 4 women, in how many ways can 3 men and 2 women or 2 men and 3 women be selected?

294.

304.

284.

314.

Soln.
Ans: a

The required count is ⁴C₃ × ⁷C₂ + ⁴C₂ × ⁷C₃ = 294.

Solution | Discuss! | Chapters»

Question 4

What is the value of ⁶P₃?

120.

130.

110.

140.

Soln.
Ans: a

⁶P₃ is ${6 !}/{(6 - 3) !}$ = 120.

Solution | Discuss! | Chapters»

Question 5

Out of given 7 consonants and 3 vowels, how many words can be formed that contain 3 consonants and 2 vowels or 3 vowels and 2 consonants?

15120.

15130.

15110.

15140.

Soln.
Ans: a

We can make the selection in ³C₃ × ⁷C₂ + ³C₂ × ⁷C₃ ways. But the five members can themselves be arranged in 5! ways. So the number of words is 120 × (³C₃ × ⁷C₂ + ³C₂ × ⁷C₃) = 15120.