Pipes and Cisterns Quiz Set 013

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Question 1

Two pipes can together fill a cistern in 5 minutes. How long does the slower alone take if the speeds of the pipes are in the ratio 4 : 1?

 A

25 mins.

 B

26 mins.

 C

24 mins.

 D

27 mins.

Soln.
Ans: a

Let the time taken by the slower pipe alone be x. Then 5 × $(1/x + 4/x)$ = 1. Solving for x, we get x = 5 × 5 = 25 mins.


Question 2

Two taps X, Y and Z can fill a tank in 18, 17 and 10 minutes respectively. All the taps are turned on at the same time. After how many minutes is the tank completely filled?

 A

$4{109/164}$ mins.

 B

$5{114/163}$ mins.

 C

$3{103/166}$ mins.

 D

$7{95/166}$ mins.

Soln.
Ans: a

Let the time be x mins. Then sum of works done by X, Y and Z = 1. $x/18 + x/17 + x/10 = 1$. Solving, we get x = $4{109/164}$. Or use the shortcut ${abc}/{ab + bc + ca}$. Another thing, instead of solving the entire calculation, you can keep an eye on the options to find the nearest answer.


Question 3

A tap can fill a tank in 2 hours. Because of a leak it took $3{1/6}$ hours to fill the tank. When the tank has been completely filled, the tap is closed. How long will the water last in the tank?

 A

$5{3/7}$ hrs.

 B

$7{1/2}$ hrs.

 C

$3{4/9}$ hrs.

 D

$6{5/9}$ hrs.

Soln.
Ans: a

Work done by the leak in one hour is $1/2 - 1/({19/6})$ = $1/2 - 6/19$ = $7/38$. So the leak will complete the whole task in ${38/7}$, which is same as: $5{3/7}$ hours.


Question 4

Two pipes, A and B, can fill a cistern in 14 and 16 mins respectively. There is a leakage tap that can drain 7 liters of water per minute. If all three of them work together, the tank is filled in 18 minutes. What is the volume of the tank?

 A

$89{25/79}$ liters.

 B

$91{37/78}$ liters.

 C

$86{11/81}$ liters.

 D

$90{1/27}$ liters.

Soln.
Ans: a

Work done by the leakage in 1 min is $1/14 + 1/16 - 1/18$ = ${79/1008}$. This work is equivalent to a volume of 7 liters. So, the total volume is 7 × ${1008/79}$ = ${7056/79}$, which is same as: $89{25/79}$ liters.


Question 5

Two pipes, A and B, can fill a bucket in 11 and 15 mins respectively. Both the pipes are opened simultaneously. The bucket is filled in 8 mins if B is turned off after how many minutes:

 A

$4{1/11}$ mins.

 B

$5{3/5}$ mins.

 C

$2{8/13}$ mins.

 D

6 mins.

Soln.
Ans: a

Let B be closed after it has been filling for x minutes. Work done by pipes A and B should add to 1. So $8/11$ + $x/15$ = 1. Solving, we get x = ${45/11}$, which is same as: $4{1/11}$.


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This Blog Post/Article "Pipes and Cisterns Quiz Set 013" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-10-26.

Posted by Parveen(Hoven),
Aptitude Trainer


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