Pipes and Cisterns Quiz Set 015 | Maths Aptitude Quiz Questions and Mock Test on Pipes and Cisterns Set 15 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

**Your Score**
Correct Answers:
Wrong Answers:
Unattempted:

Question 1

Two pipes, A and B, can fill a bucket in 13 and 14 mins respectively. Both the pipes are opened simultaneously. The bucket is filled in 6 mins if B is turned off after how many minutes:

$7{7/13}$ mins.

$9{1/4}$ mins.

$5{2/3}$ mins.

$9{2/15}$ mins.

Soln.
Ans: a

Let B be closed after it has been filling for x minutes. Work done by pipes A and B should add to 1. So $6/13$ + $x/14$ = 1. Solving, we get x = ${98/13}$, which is same as: $7{7/13}$.

Solution | Discuss! | Chapters»

Question 2

Two pipes can together fill a cistern in 4 minutes. How long does the slower alone take if the speeds of the pipes are in the ratio 4 : 1?

20 mins.

21 mins.

19 mins.

22 mins.

Soln.
Ans: a

Let the time taken by the slower pipe alone be x. Then 4 × $(1/x + 4/x)$ = 1. Solving for x, we get x = 4 × 5 = 20 mins.

Solution | Discuss! | Chapters»

Question 3

Two pipes, A and B, can fill a bucket in 19 and 5 mins respectively. Both the pipes are opened simultaneously. The bucket is filled in 11 mins if B is turned off after how many minutes:

$2{2/19}$ mins.

$3{5/18}$ mins.

1 mins.

$4{13/21}$ mins.

Soln.
Ans: a

Let B be closed after it has been filling for x minutes. Work done by pipes A and B should add to 1. So $11/19$ + $x/5$ = 1. Solving, we get x = ${40/19}$, which is same as: $2{2/19}$.

Solution | Discuss! | Chapters»

Question 4

Two taps A and B can fill a tank in 17 and 68 minutes respectively. Both the taps are turned on at the same time. After how many minutes should B be turned off so that the tank can be filled in 14 minutes?

12 mins.

13 mins.

11 mins.

15 mins.

Soln.
Ans: a

Let B be closed after x mins. Then sum of works done by A and B = 1. $14/17 + x/68 = 1$. Solving, we get x = 12.

Solution | Discuss! | Chapters»

Question 5

Two taps X, Y and Z can fill a tank in 4, 18 and 7 minutes respectively. All the taps are turned on at the same time. After how many minutes is the tank completely filled?

$2{26/113}$ mins.

$3{29/112}$ mins.

$1{24/115}$ mins.

$5{16/115}$ mins.

Soln.
Ans: a

Let the time be x mins. Then sum of works done by X, Y and Z = 1. $x/4 + x/18 + x/7 = 1$. Solving, we get x = $2{26/113}$. Or use the shortcut ${abc}/{ab + bc + ca}$. Another thing, instead of solving the entire calculation, you can keep an eye on the options to find the nearest answer.

Solution | Discuss! | Chapters»