Problems on Numbers Quiz Set 010

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Question 1

What is 0.67676767...?

 A

$67/99$.

 B

$68/99$.

 C

$67/100$.

 D

$67/101$.

Soln.
Ans: a

0.67676767... is same as $0.\ov 67$. Let y = $0.\ov 67$. Multiply by 100, 100y = 67 + $0.\ov 67$ which is same as 67 + y. So 99y = 67, ⇒ y = $67/99$. So answer = ${67/99}$.


Question 2

The sum of two numbers is 14. Their product is 45. One of the two numbers is?

 A

9.

 B

10.

 C

8.

 D

11.

Soln.
Ans: a

Let the numbers be $a$ and $14 - a$. We are given their product as a × (14 - a) = 45, which is a quadratic expression that can be simplified to $(a - 9) × (5 - a) = 0$. So the numbers could be 9 and 5.


Question 3

Which term of this arithmetic series is zero: 81, 72, 63 ...?

 A

10.

 B

11.

 C

9.

 D

12.

Soln.
Ans: a

The first term is 81, common difference is d = -9, n-th term is 0. So $0 = 81 + (n - 1) × -9$ which gives $n = 1 + {81/9} = 10$.


Question 4

When a two digit number is reversed and added to itself we get 55. The product of the digits of that number is 6. What is the number?

 A

32.

 B

33.

 C

31.

 D

34.

Soln.
Ans: a

Let the number be ab. When it is reversed and added to itself we get (10a + b) + (10b + a) = 11 × (a + b). We are given 55 = 11 × (a + b) ⇒ $a + b = 55 / 11 = 5$, so the digits are $a$ and $5 - a$. We are given their product as a × (5 - a) = 6, which is a quadratic expression that can be simplified to $(a - 3) × (2 - a) = 0$. So the number could be 32 or 23.


Question 5

The sum of three consecutive even integer numbers is 672. The middle among the three is?

 A

224.

 B

225.

 C

223.

 D

226.

Soln.
Ans: a

Let the numbers be 2n - 2, 2n and 2n + 2. The sum is 6n = 3 x 2n = 3 x middle. We are given 3 x middle = 672, ⇒ middle = $672/3$, i.e., middle = 224.


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This Blog Post/Article "Problems on Numbers Quiz Set 010" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2019-08-18.

Posted by Parveen(Hoven),
Aptitude Trainer


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