Problems on Numbers Quiz Set 011

Advertisement


Your Score
Correct Answers:
Wrong Answers:
Unattempted:

Question 1

The sum of two numbers is 53. Their difference is 19. They are in the ratio?

 A

$2{2/17}$.

 B

$3{5/16}$.

 C

1.

 D

$4{11/19}$.

Soln.
Ans: a

Let the numbers be a and b, and let their ratio be k such that $a/b = k$. We are given $a + b = 53$ ⇒ $b(k + 1) = 53$. Similarly, from the difference we can obtain $b(k - 1) = 19$. Dividing we get ${k + 1}/{k - 1} = 53/19$. By componendo and dividendo, $k = {53 + 19}/{53 - 19}$ = ${36/17}$, which is same as: $2{2/17}$.


Question 2

The sum of two numbers is 30. Their product is 161. One of the two numbers is?

 A

23.

 B

24.

 C

22.

 D

25.

Soln.
Ans: a

Let the numbers be $a$ and $30 - a$. We are given their product as a × (30 - a) = 161, which is a quadratic expression that can be simplified to $(a - 23) × (7 - a) = 0$. So the numbers could be 23 and 7.


Question 3

x should be replaced by which minimum number so that 39242x6416 is completely divisible by 3?

 A

2.

 B

3.

 C

5.

 D

4.

Soln.
Ans: a

If the above number has to be divisible by 3, the sum of the digits, i.e., 3 + 9 + 2 + 4 + 2 + x + 6 + 4 + 1 + 6, should be divisible by 3. So we can see that $x + 37$ should be divisible by 3. By inspection, x = 2.


Question 4

The sum of three consecutive odd integer numbers is 657. The middle among the three is?

 A

219.

 B

220.

 C

218.

 D

221.

Soln.
Ans: a

Let the numbers be 2n - 3, 2n - 1 and 2n + 1. The sum is 3(2n - 1) = 3 x middle. We are given 3 x middle = 657, ⇒ middle = $657/3$, i.e., middle = 219.


Question 5

Which term of this arithmetic series is zero: 70, 63, 56 ...?

 A

11.

 B

12.

 C

10.

 D

13.

Soln.
Ans: a

The first term is 70, common difference is d = -7, n-th term is 0. So $0 = 70 + (n - 1) × -7$ which gives $n = 1 + {70/7} = 11$.


buy aptitude video tutorials


Creative Commons License
This Blog Post/Article "Problems on Numbers Quiz Set 011" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2019-08-18.

Posted by Parveen(Hoven),
Aptitude Trainer


Advertisement