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### Question 1

Average weight of a group of 25 boys is 46 Kg. Later it was found that the weighing machine was showing 3 Kg more than the actual weight. What is the actual average weight?

**A**

43.

**B**

44.

**C**

42.

**D**

41.

**Soln.**

**Ans: a**

Let the total weight of the group as measured with the faulty machine be x. Then, by average formula $46 = x/25$, which gives x = $46 × 25 = 1150$. When weight of each of the 25 boys is reduced by 3 Kg, the new total becomes $1150 - 25 × 3 = 1075$, the new average becomes $1075/25 = 43$. TIP: As a shortcut, the new average = old average - error in weighing machine.

### Question 2

The average weight of 13 students of a class is 39 Kg, whereas the average weight of remaining 17 students is 30 Kg. What is the average weight of all 30 students?

**A**

$33{9/10}$.

**B**

$35{2/29}$.

**C**

$32{25/31}$.

**D**

$36{9/28}$.

**Soln.**

**Ans: a**

Total weight of 13 students is 13 × 39 = 507. Similarly, the total weight of remaining 17 students is 17 × 30 = 510. The total weight of all 30 students is 507 + 510 = 1017. So the average = 1017/30 = $33{9/10}$.

### Question 3

The average age of three friends 3 years ago was 30 years. The average age of two them 5 years ago was 13 years. What is the present age of the third friend?

**A**

63 years.

**B**

64 years.

**C**

62 years.

**D**

61 years.

**Soln.**

**Ans: a**

Let the present ages of the three friends be a, b and c. We are given ${(b - 5) + (c - 5)}/2$ = 13. Which gives b + c = 36. We are also given ${(a - 3) + (b - 3) + (c - 3)}/3$ = 30, which gives a + b + c = 3 * 30 + 9 = 99. Putting b + c here we get a = 99 - (b + c) = 99 - 36 = 63 years.

### Question 4

The sales(in rupees) of a karyana store for five consecutive days is 4392, 5040, 3630, 1554, 612. What should be the sale on the sixth day so that the overall average sale is 3179?

### Question 5

Each of the 5 boys of a class has a weight 60 Kg. If a new boy with a weight 55 Kg more than the average of all 6 boys is added, what is the sum total of the values of all 6 boys?

**A**

426 Kg.

**B**

427 Kg.

**C**

425 Kg.

**D**

424 Kg.

**Soln.**

**Ans: a**

Let the average of all 6 boys be x, then the required total is T = 6x. By averages, $x = {5 × 60 + (x + 55)}/6$ which is same as $x × 6 = {5 × 60 + (x + 55)}$, which is same as $T = {5 × 60 + (T/6 + 55)}$, solving for T we get 426 Kg.

### More Chapters | See All...

Partnerships | Stocks and Shares | Data Sufficiency | Simple Interest | Ratio and Proportion | Profit and Loss | Problems on Ages | Passwords and Inputs | Boats and Streams | Pipes and Cisterns | More...

This Blog Post/Article "Averages Quiz Set 002" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2019-08-18.