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### Question 1

The average weight of 18 students of a class is 29 Kg, whereas the average weight of remaining 12 students is 32 Kg. What is the average weight of all 30 students?

**A**

$30{1/5}$.

**B**

$31{7/29}$.

**C**

$29{7/31}$.

**D**

$32{5/14}$.

**Soln.**

**Ans: a**

Total weight of 18 students is 18 × 29 = 522. Similarly, the total weight of remaining 12 students is 12 × 32 = 384. The total weight of all 30 students is 522 + 384 = 906. So the average = 906/30 = $30{1/5}$.

### Question 2

Average weight of a group of 41 boys is 75 Kg. Later it was found that the weighing machine was showing 4 Kg more than the actual weight. What is the actual average weight?

**A**

71.

**B**

72.

**C**

70.

**D**

69.

**Soln.**

**Ans: a**

Let the total weight of the group as measured with the faulty machine be x. Then, by average formula $75 = x/41$, which gives x = $75 × 41 = 3075$. When weight of each of the 41 boys is reduced by 4 Kg, the new total becomes $3075 - 41 × 4 = 2911$, the new average becomes $2911/41 = 71$. TIP: As a shortcut, the new average = old average - error in weighing machine.

### Question 3

A, B and C are three numbers. The average of A, B and C is 31. The average of A and B is 17, and the average of B and C is 43, what is the value of number B?

### Question 4

If the average of p and q is 20, the average of q and r is 48, and of r and p is 60, then what is the value of p?

**A**

32.

**B**

33.

**C**

31.

**D**

34.

**Soln.**

**Ans: a**

We have three equations (p + q)/2 = average of pq, (q + r)/2 = average of qr and (r + p)/2 = average of rp. Adding these three we get p + q + r = (average of pq + average of qr + average of rp) = (20 + 48 + 60) = 128. So p = 128 - (q + r) = 128 - (2 × average of q and r) = 128 - 2 × 48 = 32.

### Question 5

The sales(in rupees) of a gift shop for six consecutive days is 2160, 2100, 3234, 3636, 1932 and 4266. What is the overall average sale for these six days?

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This Blog Post/Article "Averages Quiz Set 005" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2019-08-18.