Distance and Time Quiz Set 009 | Maths Aptitude Quiz Questions and Mock Test on Distance and Time Set 9 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

An aircraft was on a 2660 km journey. Its engine developed a snag so it had to slow down. It's average speed reduced by 7km/h, as a result of which it reached its destination late by 1 hour. What was the actual duration of the journey?

19 hrs.

20 hrs.

18 hrs.

21 hrs.

Soln.
Ans: a

Let x be the actual duration of the journey. Then, $2660/x - 2660/{x + 1} = 7$. Which gives 2660 × $1/{x (x + 1)} = 7$. Solving for x, or by trying the options one by one, we get x = 19 hours.

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Question 2

A boy goes to his school at an average speed of 5 km/h, and returns back at an average speed of 3 km/h. What is the average speed for the to and fro journey?

$3{3/4}$ km/h.

$6{1/3}$ km/h.

$1{5/6}$ km/h.

$4{1/2}$ km/h.

Soln.
Ans: a

If u and v are the to and fro speeds, then the standard formula is ${2uv}/{u + v}$ = ${2 × 5 × 3}/{5 + 3}$ = ${15/4}$, which is same as: $3{3/4}$ km/h.

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Question 3

A vehicle travels 50% of its distance at 4 km/h, and the remaining 50% at 8 km/h. What is the total distance, if it travelled for a total duration of 24 hours?

128 km.

129 km.

127 km.

130 km.

Soln.
Ans: a

Let 2x be the actual duration of the journey. Then, $x/4 + x/8 = 24$. Solving for x we get x = 64, and so, 2x = 128 km.

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Question 4

Speeds of A and B are in the ratio 7 : 19. What is the ratio of the times that they will take to cover a distance of 100 km?

19 : 7.

7 : 19.

19 : 100.

100 : 7.

Soln.
Ans: a

Let the speeds be 7x and 19x. The times they take to cover 100 km are $100/{7x}$ and $100/{19x}$. The ratio would be 19 : 7.

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Question 5

Bus X travels 50% faster than bus Y. They start together and meet at the same time after travelling a distance of 72km. What is the speed of the bus X, if the bus Y wasted 6 hours during its journey?

4 kmph.

5 kmph.

3 kmph.

6 kmph.

Soln.
Ans: a

Let the speed of bus X be x, and of Y be 3x/2. The difference in the times taken by them is $72/x - 72/({3x}/2)$ = 6, which becomes 72 × $1/{3x}$ = 6. Solving, we get x = 4 km/h.

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