Probability Quiz Set 004

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Question 1

A box contains 4 sky blue, 2 dark green and 8 khaki balls. What is the probability of drawing a ball that is neither dark green nor sky blue?

 A

${4/7}$.

 B

$9/14$.

 C

$5/91$.

 D

$9/91$.

Soln.
Ans: a

Total number of marbles is 14. We have to basically find the probability of picking a khaki ball, for which 8 chances are favorable. So probability = 8/14 = ${4/7}$.

Solution | Discuss! | Chapters»

Question 2

A bag contains 2 Red, 4 Blue and 8 Green marbles. What is the probability of drawing a Red marble if 2 marbles are drawn out randomly?

 A

${25/91}$.

 B

$8/14$.

 C

$26/91$.

 D

$30/91$.

Soln.
Ans: a

Total number of marbles is 14. Combinations of 2 marbles that are possible = 14C2 = ${14 × 13}/2$ = 91. If one of the two balls is red, then red + red is one possibility, and 2 × (4 + 8) are the other possibilities. So total favorable outcomes = 1 + 2 × 12 = 25, and the probability is 25/91 = ${25/91}$.

Solution | Discuss! | Chapters»

Question 3

A box contains 4 maroon, 7 sky blue and 3 dark green balls. What is the probability of drawing a ball that is neither sky blue nor maroon?

 A

${3/14}$.

 B

$4/14$.

 C

$4/91$.

 D

$8/91$.

Soln.
Ans: a

Total number of marbles is 14. We have to basically find the probability of picking a dark green ball, for which 3 chances are favorable. So probability = 3/14 = ${3/14}$.

Solution | Discuss! | Chapters»

Question 4

A box contains 8 maroon, 5 navy and 3 pink marbles. What is the probability of drawing a marble that is not pink if 2 marbles are drawn out randomly?

 A

${13/20}$.

 B

$3/16$.

 C

$14/120$.

 D

$18/120$.

Soln.
Ans: a

Total number of marbles is 16. Combinations of 2 marbles that are possible = 16C2 = ${16 × 15}/2$ = 120. Chances of drawing a non-pink ball are 13C2 = $(13 × (13 - 1))/2$ = 78. So probability = 78/120 = ${13/20}$.

Solution | Discuss! | Chapters»

Question 5

If P(E) = 0.59, then what is the probability of non-occurrence of E?

 A

0.41.

 B

0.59.

 C

0.5.

 D

0.25.

Soln.
Ans: a

P(E) + P(non-occurrence of E) is always = 1. So P(non-occurrence of E) = 1 - P(E) = 0.41.

Solution | Discuss! | Chapters»
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Updated on 2020-02-07. Published on: 2016-05-08

Posted by Parveen(Hoven),
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