Permutations and Combinations Quiz Set 015 | Maths Aptitude Quiz Questions and Mock Test on Permutations and Combinations Set 15 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

In how many ways can 8 prizes be given to 4 students if each of them is equally eligible?

4096.

4106.

4126.

4116.

Soln.
Ans: a

The first has 8 options, the second also has 8 options, and so on. This is expressed as 8 × 8 × 8 × 8, which evaluates to 4096.

Solution | Discuss! | Chapters»

Question 2

How many 4 digit numbers can be formed with a given set of 7 distinct digits?

2401.

2411.

2431.

2421.

Soln.
Ans: a

The first place has 7 options, the second place also has 7 options, and so on. This is expressed as 7 × 7 × 7 × 7, which evaluates to 2401.

Solution | Discuss! | Chapters»

Question 3

2 men are standing in front of 3 cabins. In how many ways can they enter the cabins?

11.

Soln.
Ans: a

The first has 3 options, the second has (3 - 1), and so on. This is expressed as ³P₂, which evaluates to 6.

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Question 4

There are 7 trains between two stations A and B. In how many ways can a student go from A to B and return by any of the available trains?

49.

54.

47.

50.

Soln.
Ans: a

The upward journey is possible in 7 ways, and the downward also in 7 ways. So the outcomes are 7 × 7 = 49.

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Question 5

The letters of the word 'JUPITER' have to be arranged such that the vowels come together. How many different ways are possible?

720.

730.

710.

740.

Soln.
Ans: a

This word has 7 letters, out of which 4 are consonants and 3 are vowels. The vowels have to occupy three contiguous positions. This triad can be arranged in 3! ways like this: we can place 3 vowels in first place, 2 in second place and 1 in the third place, giving 3 × 2 × 1 = 6 permutations. Next, we have to arrange the 4 consonants and the triad treated as one letter, giving 5! = 120 possibilities. So the total possibilities are 6 × 120 = 720.

Solution | Discuss! | Chapters»