Problems on Ages Quiz Set 020


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Question 1

The ratio of present ages of two monuments A and B is $4{1/2}$. After 7 years later the age of A will be 88 years. What is the present age of B?

 A

18 years.

 B

16 years.

 C

14 years.

 D

20 years.

Soln.
Ans: a

The ratio of ages of A and B is given as ${9/2}$, which is same as: $4{1/2}$. So we can write the present ages of A and B, respectively, as 9r and 2r years. 7 years later the age of A is $9r + 7 = 88$ which gives r = 9. The age of B, therefore, is 2r = 2 × 9 = 18 years.


Question 2

The sum of reciprocals of my ages 6 years back and 6 years later is ${13/160}$. What is my present age?

 A

26 years.

 B

27 years.

 C

25 years.

 D

28 years.

Soln.
Ans: a

Let the present age be x. Then $1/{x + 6} + 1/{x - 6}$ = ${13/160}$. At this stage a better option is that you try putting the given answers into this expression one by one. The other option is to simplify this expression into a quadratic equation ${2x}/{x^2 - 36}$ = ${13/160}$. This can now be solved to give x = 26 years.


Question 3

The ratio of present ages of two monuments A and B is $5{1/5}$. If the difference of their ages is 105, then what is the age of B?

 A

25 years.

 B

20 years.

 C

15 years.

 D

30 years.

Soln.
Ans: a

The ratio of ages of A and B is given as ${26/5}$, which is same as: $5{1/5}$. So we can write the present ages of A and B, respectively, as 26r and 5r years. The difference is $26r - 5r = 105$ which gives r = 5. The age of B, therefore, is 5r = 5 × 5 = 25 years.


Question 4

Mr. X became a voter at the age of 18. He got married at the age of 32. What was his average age during these two points of his life?

 A

25 years.

 B

26 years.

 C

24 years.

 D

14 years.

Soln.
Ans: a

The average is simply ${18 + 32}/2$ = 25 years.


Question 5

The ages of three friends are in the ratio 17:2:13. What is the age of the youngest friend if the sum of their ages is 128 years?

 A

8 years.

 B

9 years.

 C

7 years.

 D

10 years.

Soln.
Ans: a

Let the ages of three friends be 17r, 2r and 13r. The youngest of these is 2r. We have been given their sum. So (17 + 2 + 13)r = 128. Solving, we get r = 4. The youngest is 2 × 4 = 8 years.


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Updated on 2020-02-07. Published on: 2016-04-23

Posted by Parveen(Hoven),
Aptitude Trainer


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