Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

The sum of ages of two friends is 13, whereas the product of their ages is 42. What is the sum of squares of their ages?

### Question 2

The ages of three friends are in the ratio 19:2:3. What is the age of the youngest friend if the sum of their ages 5 years back was 129 years?

**A**

12 years.

**B**

13 years.

**C**

11 years.

**D**

14 years.

**Soln.**

**Ans: a**

Let the ages of three friends be 19r, 2r and 3r. The youngest of these is 2r. We have been given their sum 5 years back. So (19 + 2 + 3)r - (3 × 5) = 129. Solving, we get r = 6. The youngest is 2 × 6 = 12 years.

### Question 3

The ratio of present ages of two monuments A and B is $2{1/9}$. If the difference of their ages is 90, then what is the age of B?

**A**

81 years.

**B**

72 years.

**C**

63 years.

**D**

90 years.

**Soln.**

**Ans: a**

The ratio of ages of A and B is given as ${19/9}$, which is same as: $2{1/9}$. So we can write the present ages of A and B, respectively, as 19r and 9r years. The difference is $19r - 9r = 90$ which gives r = 9. The age of B, therefore, is 9r = 9 × 9 = 81 years.

### Question 4

The age of father tortoise is 14 times the age of his son. After 50 years his age will be 4 times the age of his son. What would be the ratio of their ages 180 years from today?

**A**

2.

**B**

5.

**C**

3.

**D**

4.

**Soln.**

**Ans: a**

If the age of the son today is s, the age of the father is 14s. After 50 years, we have 14s + 50 = 4(s + 50). Solving for s, we get s = 15 years. The ratio of their ages after 180 years = ${14s + 180}/{s + 180}$. Substituting s and simplifying we get the ratio as 2.

### Question 5

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 114. What is the age of the middle friend today?

This Blog Post/Article "Problems on Ages Quiz Set 016" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2017-06-24.