Correct Answers: | |

Wrong Answers: | |

Unattempted: |

### Question 1

The sum of the ages of 10 calves of a whale born at a gap of 4 years is 280. What is the age of the youngest calf?

**A**

10 years.

**B**

11 years.

**C**

9 years.

**D**

12 years.

**Soln.**

**Ans: a**

The ages of the calves are in an AP with d = 4, n = 10, and sum S = 280. We have to find the first term a. We know S = ${n/2} × (2a + (n-1)d)$ Putting the values 280 = ${10/2} × (2a + (10-1)×4)$. Solving, get a = 10 years.

### Question 2

The ages of three friends are in the ratio 2:23:3. What is the age of the youngest friend if the sum of their ages 3 years back was 159 years?

**A**

12 years.

**B**

13 years.

**C**

11 years.

**D**

14 years.

**Soln.**

**Ans: a**

Let the ages of three friends be 2r, 23r and 3r. The youngest of these is 2r. We have been given their sum 3 years back. So (2 + 23 + 3)r - (3 × 3) = 159. Solving, we get r = 6. The youngest is 2 × 6 = 12 years.

### Question 3

The ratio of present ages of two monuments A and B is $2{9/10}$. After 4 years later the age of A will be 381 years. What is the present age of B?

**A**

130 years.

**B**

120 years.

**C**

110 years.

**D**

140 years.

**Soln.**

**Ans: a**

The ratio of ages of A and B is given as ${29/10}$, which is same as: $2{9/10}$. So we can write the present ages of A and B, respectively, as 29r and 10r years. 4 years later the age of A is $29r + 4 = 381$ which gives r = 13. The age of B, therefore, is 10r = 10 × 13 = 130 years.

### Question 4

The ratio of present ages of two monuments A and B is $2{1/4}$. After 3 years later the age of A will be 102 years. What is the present age of B?

**A**

44 years.

**B**

40 years.

**C**

36 years.

**D**

48 years.

**Soln.**

**Ans: a**

The ratio of ages of A and B is given as ${9/4}$, which is same as: $2{1/4}$. So we can write the present ages of A and B, respectively, as 9r and 4r years. 3 years later the age of A is $9r + 3 = 102$ which gives r = 11. The age of B, therefore, is 4r = 4 × 11 = 44 years.

### Question 5

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 99. What is the age of the middle friend today?

### More Chapters | See All...

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This Blog Post/Article "Problems on Ages Quiz Set 018" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.

Updated on 2019-08-18.