Distance and Time Quiz Set 012 | Maths Aptitude Quiz Questions and Mock Test on Distance and Time Set 12 | mock tests for Bank PO, SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

Two cars, A and B, start to move towards each other. If they meet when A has travelled $(1/5)$^th of the distance, what is the ratio of the speed of B to the speed of A?

Soln.
Ans: a

Let the speeds of the cars be u and v and the initial distance between them be L. When they meet they have travelled for the same time. So $(L/5)/u = ({4L}/5)/v$. The ratio $v/u$ = 4.

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Question 2

Two cars A and B begin to move towards each other and meet midway after travelling equal distance. What is the initial distance between them if the speeds of A and B are 2 km/h and 8 km/h, and B started 1 hour late?

$5{1/3}$ km.

$9{1/2}$ km.

$4{1/3}$ km.

5 km.

Soln.
Ans: a

If the distance between them is L, they meet after travelling L/2. Equating the times they travelled, $L/{2 × 2} = L/{2 × 8} + 1$. Solving for L we get L = $5{1/3}$ km.

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Question 3

A vehicle travels 50% of its distance at 5 km/h, and the remaining 50% at 11 km/h. What is the total distance, if it travelled for a total duration of 32 hours?

220 km.

221 km.

219 km.

222 km.

Soln.
Ans: a

Let 2x be the actual duration of the journey. Then, $x/5 + x/11 = 32$. Solving for x we get x = 110, and so, 2x = 220 km.

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Question 4

Speeds of A and B are in the ratio 17 : 11. What is the speed of A if B can cover a distance of 55 Km in 1 hour?

85 kmph.

86 kmph.

84 kmph.

87 kmph.

Soln.
Ans: a

The speed of B is 55/1 = 55 km/h. So, the speed of A = ${17 × 55}/11$ = 85 km/h.

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Question 5

A train passes two persons walking in the same direction as the train. The time it takes to move past the man running at 13km/h is 19sec, whereas the time it takes to cross the other man running at 26km/h is 20sec. What is the speed of the train?

273km/h.

274km/h.

272km/h.

275km/h.

Soln.
Ans: a

Let the speed of the train be v km/h. Length of the train calculated with the data for the first man = $(v - 13) × 19$. It should equal the length obtained from the data for the second man. So $(v - 13) × 19$ = $(v - 26) × 20$. Please note that we have not converted seconds to hours because that factor will ultimately cancel away. Solving for v we get 273km/h.

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