Problems on Ages Quiz Set 003

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Question 1

The ages of two friends are 4 and 16 years respectively. They are looking for a special third friend whose age is in-between their ages. What should be the age of the third friend if the ages of all three have to be in a GP(geometric progression)?

 A

8 years.

 B

9 years.

 C

7 years.

 D

10 years.

Soln.
Ans: a

If the age of the third friend is x. Then for a GP, x = $√(4 × 16)$ = 8 years.


Question 2

5 years back the ratio of ages of X and Y was ${35/43}$. The ratio of their ages 3 years from now would be ${43/51}$. What is the present age of X?

 A

40 years.

 B

41 years.

 C

39 years.

 D

42 years.

Soln.
Ans: a

Let their present ages be x and y. Then ${x - 5}/{y - 5} = $ ${35/43}$. Similarly, ${x + 3}/{y + 3} = $ ${43/51}$. Solving these equations for x and y, we get y = 48, and x = 40 years as the answer.


Question 3

My father was 25 years old when I was born. My mother's age was 23 when my sister, who is 2 years younger to me, was born. What is the difference between the ages of my parents?

 A

4 years.

 B

5 years.

 C

3 years.

 D

6 years.

Soln.
Ans: a

If the age of my father is F, then my age is F - 25, so my younger sister's age is (F - 25) - 2, which is = F - 27. If my mother's age is M, then M = (my sister's age) + 23, i.e., M = (F - 27) + 23. We get F - M = 4 years.

This question can be solved directly also. The age of my father at the time of birth of my sister was 25 + 2 = 27. At the time my mother was 23 years. So the difference between their ages = 27 - 23 = 4 years.


Question 4

The age of father tortoise is 10 times the age of his son. After 12 years his age will be 6 times the age of his son. What would be the ratio of their ages 120 years from today?

 A

2.

 B

5.

 C

3.

 D

4.

Soln.
Ans: a

If the age of the son today is s, the age of the father is 10s. After 12 years, we have 10s + 12 = 6(s + 12). Solving for s, we get s = 15 years. The ratio of their ages after 120 years = ${10s + 120}/{s + 120}$. Substituting s and simplifying we get the ratio as 2.


Question 5

The age of father tortoise is 14 times the age of his son. After 40 years his age will be 6 times the age of his son. What would be the ratio of their ages 300 years from today?

 A

2.

 B

5.

 C

3.

 D

4.

Soln.
Ans: a

If the age of the son today is s, the age of the father is 14s. After 40 years, we have 14s + 40 = 6(s + 40). Solving for s, we get s = 25 years. The ratio of their ages after 300 years = ${14s + 300}/{s + 300}$. Substituting s and simplifying we get the ratio as 2.


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This Blog Post/Article "Problems on Ages Quiz Set 003" by Parveen (Hoven) is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
Updated on 2017-10-26.

Posted by Parveen(Hoven),
Aptitude Trainer


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