Problems on Ages Quiz Set 002 | Maths Aptitude Mock Test on Problems of Ages Set 2 | mock tests for Bank PO, SSB/SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

When the daughter was born, the age of her mother was same as the daughter's age today. What was the age of the daughter 5 years back, if the age of the mother today is 44 years?

17 years.

18 years.

16 years.

19 years.

Soln.
Ans: a

Clearly, the age of the mother is twice her daughter's present age. So the daughter's age today is 44/2 = 22 years. And, 5 years back the age of the daughter was 22 - 5 = 17 years.

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Question 2

The ages of three friends are in the ratio 13:11:2. What is the age of the youngest friend if the sum of their ages is 52 years?

4 years.

5 years.

3 years.

6 years.

Soln.
Ans: a

Let the ages of three friends be 13r, 11r and 2r. The youngest of these is 2r. We have been given their sum. So (13 + 11 + 2)r = 52. Solving, we get r = 2. The youngest is 2 × 2 = 4 years.

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Question 3

The square root of twice my present age is equal to the sum of the square roots of my ages 8 years back and 8 years hence. What is my present age?

8 years.

9 years.

7 years.

16 years.

Soln.
Ans: a

Let the present age be x. Then $√(x - 8) + √(x + 8)$ = $√{2x}$. Squaring both sides, $(√(x - 8))^2 + (√(x + 8))^2 + 2√{x^2 - 8^2}$ = $2x$ which gives $x - 8 + x + 8 + 2√{x^2 - 8^2}$ = $2x$. Cancelling, and simplifying, $2√(x^2 - 64) = 0$, which leads to x = 8 years.

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Question 4

After 5 years from today the ages of three friends will be in an AP(arithmetic progression), and their sum would be 45. What is the age of the middle friend today?

10 years.

11 years.

9 years.

12 years.

Soln.
Ans: a

Let the ages after 5 years be a - d, a and a + d. The sum is given to us. So (a - d) + a + (a + d) = 3a = 45. We get a = 45/3 = 15. So, the age of the middle friend today is a - 5 = 10 years.

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Question 5

The ages of two friends are 9 and 16 years respectively. They are looking for a special third friend whose age is in-between their ages. What should be the age of the third friend if the ages of all three have to be in a GP(geometric progression)?

12 years.

13 years.

11 years.

14 years.

Soln.
Ans: a

If the age of the third friend is x. Then for a GP, x = $√(9 × 16)$ = 12 years.

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