Problems on Ages Quiz Set 012 | Maths Aptitude Mock Test on Problems of Ages Set 12 | mock tests for Bank PO, SSB/SSC Exams, SO Clerical Exam, GATE Exam, LIC AO, GIC AO, etc.

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Question 1

The sum of the ages of 12 calves of a whale born at a gap of 8 years is 672. What is the age of the youngest calf?

12 years.

13 years.

11 years.

14 years.

Soln.
Ans: a

The ages of the calves are in an AP with d = 8, n = 12, and sum S = 672. We have to find the first term a. We know S = ${n/2} × (2a + (n-1)d)$ Putting the values 672 = ${12/2} × (2a + (12-1)×8)$. Solving, get a = 12 years.

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Question 2

Mr. X became a voter at the age of 18. He got married at the age of 24. What was his average age during these two points of his life?

21 years.

22 years.

20 years.

6 years.

Soln.
Ans: a

The average is simply ${18 + 24}/2$ = 21 years.

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Question 3

The ages of three friends are in the ratio 3:7:5. What is the age of the youngest friend if the sum of their ages 6 years back was 57 years?

15 years.

16 years.

14 years.

17 years.

Soln.
Ans: a

Let the ages of three friends be 3r, 7r and 5r. The youngest of these is 3r. We have been given their sum 6 years back. So (3 + 7 + 5)r - (3 × 6) = 57. Solving, we get r = 5. The youngest is 3 × 5 = 15 years.

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Question 4

The ratio of present ages of two monuments A and B is $3{2/5}$. If the difference of their ages is 120, then what is the age of B?

50 years.

45 years.

40 years.

55 years.

Soln.
Ans: a

The ratio of ages of A and B is given as ${17/5}$, which is same as: $3{2/5}$. So we can write the present ages of A and B, respectively, as 17r and 5r years. The difference is $17r - 5r = 120$ which gives r = 10. The age of B, therefore, is 5r = 5 × 10 = 50 years.

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Question 5

The ages of two friends are 3 and 27 years respectively. They are looking for a special third friend whose age is in-between their ages. What should be the age of the third friend if the ages of all three have to be in a GP(geometric progression)?

9 years.

10 years.

8 years.

11 years.

Soln.
Ans: a

If the age of the third friend is x. Then for a GP, x = $√(3 × 27)$ = 9 years.

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